1990 Maryland gubernatorial election

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Maryland gubernatorial election, 1990

← 1986 November 6, 1990 1994 →
  William Donald Schaefer.jpg No image.svg
Nominee William Donald Schaefer William S. Shepard
Party Democratic Republican
Running mate Melvin Steinberg Lois Shepard
Popular vote 664,015 446,980
Percentage 59.76% 40.23%

Governor before election

William Donald Schaefer
Democratic

Elected Governor

William Donald Schaefer
Democratic

The 1990 Maryland gubernatorial election was held on November 6, 1990. Incumbent Democrat William Donald Schaefer defeated Republican nominee William S. Shepard with 40.23% of the vote.

Primary elections[edit]

Primary elections were held on September 11, 1990.[1]

Democratic primary[edit]

Candidates[edit]

Results[edit]

Democratic primary results[1]
Party Candidate Votes %
Democratic William Donald Schaefer 358,534 78.05
Democratic Frederick M. Grisser Jr. 100,816 21.95
Total votes 459,350 100.00

Republican primary[edit]

Candidates[edit]

Results[edit]

Republican Party primary results[1]
Party Candidate Votes %
Republican William S. Shepard 66,966 52.72
Republican Ross Zimmerman Pierpont 60,065 47.28
Total votes 127,031 100.00

General election[edit]

Candidates[edit]

  • William Donald Schaefer, Democratic
  • William S. Shepard, Republican

Results[edit]

Maryland gubernatorial election, 1990[2]
Party Candidate Votes % ±
Democratic William Donald Schaefer 664,015 59.76%
Republican William S. Shepard 446,980 40.23%
Majority 217,035
Turnout 1,111,088
Democratic hold Swing

References[edit]

  1. ^ a b c "1990 Gubernatorial Primary Election Results". Elections.maryland.gov. Retrieved 2018-11-11.
  2. ^ "1990 Gubernatorial General Election Results". Elections.maryland.gov. Retrieved 2018-11-11.