Illustration of the midpoint method assuming that
equals the exact value
The midpoint method computes
so that the red chord is approximately parallel to the tangent line at the midpoint (the green line).
In numerical analysis, a branch of applied mathematics, the midpoint method is a one-step method for numerically solving the differential equation,
The explicit midpoint method is given by the formula
the implicit midpoint method by
for Here, is the step size — a small positive number, and is the computed approximate value of The explicit midpoint method is also known as the modified Euler method, the implicit method is the most simple collocation method, and, applied to Hamiltonian dynamics, a symplectic integrator.
The name of the method comes from the fact that in the formula above, the function giving the slope of the solution is evaluated at the midpoint between at which the value of is known and at which the value of needs to be found.
A geometric interpretation may give a better intuitive understanding of the method (see figure at right). In the basic Euler's method, the tangent of the curve at is computed using . The next value is found where the tangent intersects the vertical line . However, if the second derivative is only positive between and , or only negative (as in the diagram), the curve will increasingly veer away from the tangent, leading to larger errors as increases. The diagram illustrates that the tangent at the midpoint (upper, green line segment) would most likely give a more accurate approximation of the curve in that interval. However, this midpoint tangent could not be accurately calculated because we do not know the curve (that is what is to be calculated). Instead, this tangent is estimated by using the original Euler's method to estimate the value of at the midpoint, then computing the slope of the tangent with . Finally, the improved tangent is used to calculate the value of from . This last step is represented by the red chord in the diagram. Note that the red chord is not exactly parallel to the green segment (the true tangent), due to the error in estimating the value of at the midpoint.
The local error at each step of the midpoint method is of order , giving a global error of order . Thus, while more computationally intensive than Euler's method, the midpoint method's error generally decreases faster as .
The methods are examples of a class of higher-order methods known as Runge–Kutta methods.
Derivation of the midpoint method
Illustration of numerical integration for the equation
Blue: the Euler method
, green: the midpoint method, red: the exact solution,
The step size is
The same illustration for
It is seen that the midpoint method converges faster than the Euler method.
The midpoint method is a refinement of the Euler's method
and is derived in a similar manner.
The key to deriving Euler's method is the approximate equality
which is obtained from the slope formula
and keeping in mind that
For the midpoint methods, one replaces (3) with the more accurate
when instead of (2) we find
One cannot use this equation to find as one does not know at . The solution is then to use a Taylor series expansion exactly as if using the Euler method to solve for :
which, when plugged in (4), gives us
and the explicit midpoint method (1e).
The implicit method (1i) is obtained by approximating the value at the half step by the midpoint of the line segment from to
Inserting the approximation for
results in the implicit Runge-Kutta method
which contains the implicit Euler method with step size as its first part.
Because of the time symmetry of the implicit method, all
terms of even degree in of the local error cancel, so that the local error is automatically of order . Replacing the implicit with the explicit Euler method in the determination of results again in the explicit midpoint method.