# Minkowski's bound

In algebraic number theory, Minkowski's bound gives an upper bound of the norm of ideals to be checked in order to determine the class number of a number field K. It is named for the mathematician Hermann Minkowski.

## Definition

Let D be the discriminant of the field, n be the degree of K over ${\displaystyle \mathbb {Q} }$, and ${\displaystyle 2r_{2}=n-r_{1}}$ be the number of complex embeddings where ${\displaystyle r_{1}}$ is the number of real embeddings. Then every class in the ideal class group of K contains an integral ideal of norm not exceeding Minkowski's bound

${\displaystyle M_{K}={\sqrt {|D|}}\left({\frac {4}{\pi }}\right)^{r_{2}}{\frac {n!}{n^{n}}}\ .}$

Minkowski's constant for the field K is this bound MK.[1]

## Properties

Since the number of integral ideals of given norm is finite, the finiteness of the class number is an immediate consequence,[1] and further, the ideal class group is generated by the prime ideals of norm at most MK.

Minkowski's bound may be used to derive a lower bound for the discriminant of a field K given n, r1 and r2. Since an integral ideal has norm at least one, we have 1 ≤ MK, so that

${\displaystyle {\sqrt {|D|}}\geq \left({\frac {\pi }{4}}\right)^{r_{2}}{\frac {n^{n}}{n!}}\geq \left({\frac {\pi }{4}}\right)^{n/2}{\frac {n^{n}}{n!}}\ .}$

For n at least 2, it is easy to show that the lower bound is greater than 1, so we obtain Minkowski's Theorem, that the discriminant of every number field, other than Q, is non-trivial. This implies that the field of rational numbers has no unramified extension.

## Proof

The result is a consequence of Minkowski's theorem.

## References

1. ^ a b Pohst & Zassenhaus (1989) p.384