Boundary Islet

From Wikipedia, the free encyclopedia
  (Redirected from North East Islet)
Jump to: navigation, search
Boundary Islet
Hogan Island map.png
Map of Hogan Group showing Boundary Islet
Boundary Islet is located in Tasmania
Boundary Islet
Boundary Islet
Location of the Boundary Islet in Bass Strait
Location Bass Strait
Coordinates 39°11′55″S 147°1′17″E / 39.19861°S 147.02139°E / -39.19861; 147.02139Coordinates: 39°11′55″S 147°1′17″E / 39.19861°S 147.02139°E / -39.19861; 147.02139
Archipelago Hogan Group
Area 2 ha (4.9 acres)
Length 85 m (279 ft)
States Tasmania and Victoria

Boundary Islet, historically known as North East Islet, part of the Hogan Island Group, is a two-hectare (4.9-acre) islet that straddles the border of the Australian states of Victoria and Tasmania.

The islet is Tasmania's only land boundary, and at 85 metres (279 ft) long, it is the shortest land border between any Australian states or territory.[1]

It is located at latitude 39°12′ S, about 56 kilometres (35 mi) east of the southernmost point of mainland Victoria. The boundary between Victoria and Tasmania is a parallel similarly at latitude 39°12′.[2][3] The position of the island was surveyed in 1801 by Captain John Black, who erred in placing the islet further north than it is. It was later found that the border at 39°12′ S passed through the islet.

See also[edit]


  1. ^ Jacobs, Frank (April 24, 2012). "One Island, Two Countries". The New York Times. 
  2. ^ Moore, Garry (April 2014). "The boundary between Tasmania and Victoria: Uncertainties and their possible resolution" (PDF). Traverse. The Institute of Surveyors Victoria (294). Retrieved 2015-04-10. 
  3. ^ Taylor, Greg; Economou, Nicholas (2006). The Constitution of Victoria. Federation Press. pp. 17–. ISBN 978-1-86287-612-5.