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For a gentler introduction, see P versus NP problem.

NP-hardness (non-deterministic polynomial-time hard), in computational complexity theory, is a class of problems that are, informally, "at least as hard as the hardest problems in NP". More precisely, a problem H is NP-hard when every problem L in NP can be reduced in polynomial time to H.[clarification needed][1]:80[2] As a consequence, finding a polynomial algorithm to solve any NP-hard problem would give polynomial algorithms for all the problems in NP, which is unlikely as many of them are considered hard.[3]

A common mistake [weasel words] is thinking that the NP in "NP-hard" stands for "non-polynomial". Although it is widely suspected that there are no polynomial-time algorithms for NP-hard problems, this has never been proven. Moreover, the class NP also contains the set of P in which all problems can be solved in polynomial time.[citation needed] NP in fact stands for "Nondeterministic Polynomial time."


A decision problem H is NP-hard when for every problem L in NP, there is a polynomial-time reduction from L to H[1]:80 An equivalent definition is to require that every problem L in NP can be solved in polynomial time by an oracle machine with an oracle for H.[4] Informally, we can think of an algorithm that can call such an oracle machine as a subroutine for solving H, and solves L in polynomial time, if the subroutine call takes only one step to compute.

Another definition is to require that there is a polynomial-time reduction from an NP-complete problem G to H.[1]:91 As any problem L in NP reduces in polynomial time to G, L reduces in turn to H in polynomial time so this new definition implies the previous one. It does not restrict the class NP-hard to decision problems, for instance it also includes search problems, or optimization problems.


  • If P ≠ NP, then NP-hard problems cannot be solved in polynomial time;
  • If an optimization problem H has an NP-complete decision version L, then H is NP-hard.


An example of an NP-hard problem is the decision subset sum problem, which is this: given a set of integers, does any non-empty subset of them add up to zero? That is a decision problem, and happens to be NP-complete. Another example of an NP-hard problem is the optimization problem of finding the least-cost cyclic route through all nodes of a weighted graph. This is commonly known as the traveling salesman problem.[5]

There are decision problems that are NP-hard but not NP-complete, for example the halting problem. This is the problem which asks "given a program and its input, will it run forever?" That is a yes/no question, so this is a decision problem. It is easy to prove that the halting problem is NP-hard but not NP-complete. For example, the Boolean satisfiability problem can be reduced to the halting problem by transforming it to the description of a Turing machine that tries all truth value assignments and when it finds one that satisfies the formula it halts and otherwise it goes into an infinite loop. It is also easy to see that the halting problem is not in NP since all problems in NP are decidable in a finite number of operations, while the halting problem, in general, is undecidable. There are also NP-hard problems that are neither NP-complete nor undecidable. For instance, the language of True quantified Boolean formulas is decidable in polynomial space, but not non-deterministic polynomial time (unless NP = PSPACE).[6]

NP-naming convention[edit]

NP-hard problems do not have to be elements of the complexity class NP. As NP plays a central role in computational complexity, it is used as the basis of several classes:

Class of computational problems for which a given solution can be verified as a solution in polynomial time by a deterministic Turing machine.
Class of problems which are at least as hard as the hardest problems in NP. Problems that are NP-hard do not have to be elements of NP; indeed, they may not even be decidable.
Class of problems which contains the hardest problems in NP. Each NP-complete problem has to be in NP.
At most as hard as NP, but not necessarily in NP, since they may not be decision problems.
Problems that are both NP-hard and NP-easy, but not necessarily in NP, since they may not be decision problems.
If P and NP are different, then there exist problems in the region of NP that fall between P and the NP-complete problems. (If P and NP are the same class, then NP-intermediate problems do not exist.)

Application areas[edit]

NP-hard problems are often tackled with rules-based languages in areas including:


  1. ^ a b c Leeuwen, Jan van, ed. (1998). Handbook of Theoretical Computer Science. Vol. A, Algorithms and complexity. Amsterdam: Elsevier. ISBN 0262720140. OCLC 247934368. 
  2. ^ Knuth, Donald (1974). "Postscript about NP-hard problems". ACM SIGACT News. 6 (2): 15–16. doi:10.1145/1008304.1008305. Retrieved 30 January 2016. 
  3. ^ Daniel Pierre Bovet; Pierluigi Crescenzi. Introduction to the Theory of Complexity. Prentice Hall. p. 69. ISBN 0-13-915380-2. 
  4. ^ V. J. Rayward-Smith (1986). A First Course in Computability. Blackwell. p. 159. ISBN 0-632-01307-9. 
  5. ^ Lawler, E. L.; Lenstra, J. K.; Rinnooy Kan, A. H. G.; Shmoys, D. B. (1985), The Traveling Salesman Problem: A Guided Tour of Combinatorial Optimization, John Wiley & Sons, ISBN 0-471-90413-9 .
  6. ^ More precisely, this language is PSPACE-complete; see e.g. Wegener, Ingo (2005), Complexity Theory: Exploring the Limits of Efficient Algorithms, Springer, p. 189, ISBN 9783540210450 .