Oak Grove Township, Benton County, Indiana

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Oak Grove Township
Location of Oak Grove Township in Benton County
Location of Oak Grove Township in Benton County
Coordinates: 40°31′09″N 87°15′54″W / 40.51917°N 87.26500°W / 40.51917; -87.26500Coordinates: 40°31′09″N 87°15′54″W / 40.51917°N 87.26500°W / 40.51917; -87.26500
CountryUnited States
OrganizedJuly 1840
 • TypeIndiana township
 • Total35.53 sq mi (92.0 km2)
 • Land35.51 sq mi (92.0 km2)
 • Water0.02 sq mi (0.05 km2)
Elevation748 ft (228 m)
 • Total1,581
 • Density44.5/sq mi (17.2/km2)
Time zoneUTC-5 (EST)
 • Summer (DST)UTC-4 (EDT)
FIPS code18-55620[2]
GNIS feature ID453681

Oak Grove Township is one of eleven townships in Benton County, Indiana. As of the 2010 census, its population was 1,581 and it contained 705 housing units.[3] It was one of the first three townships originally created by the county's commissioners in 1840.[4] It takes its name from White Oak Grove which grew southwest of Oxford.[5]


According to the 2010 census, the township has a total area of 35.53 square miles (92.0 km2), of which 35.51 square miles (92.0 km2) (or 99.94%) is land and 0.02 square miles (0.052 km2) (or 0.06%) is water.[3]

Cities and towns[edit]

Unincorporated towns[edit]

Adjacent townships[edit]

Major highways[edit]


The township contains two cemeteries: Justus and Oxford.


  1. ^ "US Board on Geographic Names". United States Geological Survey. 2007-10-25. Retrieved 2008-01-31.
  2. ^ "American FactFinder". United States Census Bureau. Archived from the original on September 11, 2013. Retrieved 2008-01-31.
  3. ^ a b "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Retrieved 2013-05-10.
  4. ^ Birch, Jesse Setlington (1942) [1928]. History of Benton County and Historic Oxford. Oxford, Indiana: Craw & Craw, Inc. p. 20.
  5. ^ Andreas, Alfred Theodore (1876). "Benton County". Illustrated Historical Atlas of the State of Indiana. Chicago: Baskin, Forster & Company.

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