|Nickname: Joannett Island|
The island Pana Tinani in the Louisiade Archipelago.
|Adjacent bodies of water||Solomon Sea|
|Area||78 km2 (30 sq mi)|
|Length||19 km (11.8 mi)|
|Width||6 km (3.7 mi)|
|Highest elevation||338 m (1,109 ft)|
|Highest point||Mount Guyuba|
|LLG ||Yaleyamba Rural Local Level Government Area|
|Island Group||Pana Tinani Group|
|Pop. density||9.5 /km2 (24.6 /sq mi)|
|Ethnic groups||Papauans, Austronesians, Melanesians.|
|ISO Code = PG-MBA|
The island has an area of 78 km2, making it the sixth largest island of the Louisiade Archipelago. The island is hilly, rising to 338 m at Mt. Guyuba. The island is 3.1 km north of Vanatinai, and separated from it with the Bulami Channel. It is also 100 meters east of Nigao, the easternmost island in the Calvados Chain. separated with the Magamaga Channel.
The island was discovered in the late 18th century, named after the wife of the explorer Joannett.
At the census of population in 2014, the island had 740 inhabitants, spread across 11 villages. The main town is Bwailahina (formerly Hebwaun) on the southeast coast. The island's population is administered by 2 wards : Nimoa Ward, Wanim Ward.
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