Saybrook Township, Ashtabula County, Ohio

From Wikipedia, the free encyclopedia
Jump to: navigation, search
Saybrook Township, Ashtabula County, Ohio
Lake Erie shoreline with Coast Guard personnel
Lake Erie shoreline with Coast Guard personnel
Location of Saybrook Township in Ashtabula County
Location of Saybrook Township in Ashtabula County
Coordinates: 41°51′58″N 80°50′56″W / 41.86611°N 80.84889°W / 41.86611; -80.84889Coordinates: 41°51′58″N 80°50′56″W / 41.86611°N 80.84889°W / 41.86611; -80.84889
Country United States
State Ohio
County Ashtabula
 • Total 31.9 sq mi (82.5 km2)
 • Land 31.8 sq mi (82.4 km2)
 • Water 0.04 sq mi (0.1 km2)
Elevation[1] 630 ft (192 m)
Population (2010)
 • Total 9,853
 • Density 310/sq mi (119.6/km2)
Time zone Eastern (EST) (UTC-5)
 • Summer (DST) EDT (UTC-4)
FIPS code 39-70646[2]
GNIS feature ID 1085742[1]

Saybrook Township is one of the twenty-seven townships of Ashtabula County, Ohio, United States. The 2010 census found 9,853 people in the township.[3]


Located on the northeastern edge of the county along Lake Erie, it borders the following townships:

The Canadian province of Ontario lies across Lake Erie to the north.

Part of the city of Ashtabula is located in northeastern Saybrook Township, along the shoreline of Lake Erie.

Name and history[edit]

Named for the Connecticut Saybrook Colony[4] it is the only Saybrook Township statewide.[5]

Saybrook Township was originally part of Austinburg Township and contained a settlement called Wrightsburg. It was not until 1816 that modern Saybrook Township became a separate township of its own. The township and community continued to be called Wrightsburg until 1827 when the name was changed to Saybrook, its new name coming from Saybrook, Connecticut. The early settlers are listed in the 1820 census for Ashtabula County with the township recorded as Wrightsburg.[6]

The Saybrook Township lands were originally owned by Connecticut Land Company investor William Hart. Hart then sold the entire township, with the exception of one lot, to Josiah Wright and his son Samuel Wright of Pownal, Vermont, in 1811. The deed for this sale is recorded in the Ashtabula County Courthouse in Jefferson, Ohio.

Even though the Wrights were early owners of Saybrook Township, they were not the first settlers.[citation needed] The first settler in Saybrook Township was George Webster, a New Yorker who came in 1810.[4]

In 1833, Saybrook Township contained one store, three taverns, a saw mill, and a carding machine.[7]


The township is governed by a three-member board of trustees, who are elected in November of odd-numbered years to a four-year term beginning on the following January 1. Two are elected in the year after the presidential election and one is elected in the year before it. There is also an elected township fiscal officer,[8] who serves a four-year term beginning on April 1 of the year after the election, which is held in November of the year before the presidential election. Vacancies in the fiscal officership or on the board of trustees are filled by the remaining trustees. Currently, the board is composed of chairman Norman Jepson and members Robert Brobst and Gloria Baum.[4]


  1. ^ a b "US Board on Geographic Names". United States Geological Survey. 2007-10-25. Retrieved 2008-01-31. 
  2. ^ "American FactFinder". United States Census Bureau. Retrieved 2008-01-31. 
  3. ^ "Geographic Identifiers: 2010 Demographic Profile Data (G001): Saybrook township, Ashtabula County, Ohio". U.S. Census Bureau, American Factfinder. Retrieved July 9, 2013. 
  4. ^ a b c Ashtabula County, Ohio Ashtabula County, 2007. Accessed 2007-05-28.
  5. ^ "Detailed map of Ohio" (PDF). United States Census Bureau. 2000. Retrieved 2007-02-16. 
  6. ^ Ashtabula County, Ohio 1820 Federal Census Ashtabula County, Ohio 1820 Federal Census.
  7. ^ Kilbourn, John (1833). "The Ohio Gazetteer, or, a Topographical Dictionary". Scott and Wright. p. 410. Retrieved 12 December 2013. 
  8. ^ §503.24, §505.01, and §507.01 of the Ohio Revised Code. Accessed 4/30/2009.

External links[edit]