In classical mechanics, the shell theorem gives gravitational simplifications that can be applied to objects inside or outside a spherically symmetrical body. This theorem has particular application to astronomy.
- A spherically symmetric body affects external objects gravitationally as though all of its mass were concentrated at a point at its centre.
- If the body is a spherically symmetric shell (i.e., a hollow ball), no net gravitational force is exerted by the shell on any object inside, regardless of the object's location within the shell.
A corollary is that, inside a solid sphere of constant density, the gravitational force varies linearly with distance from the centre, becoming zero by symmetry at the centre of mass.
This is easy to see: take a point within such a sphere, at a distance from the centre of the sphere, then you can ignore all the shells of greater radius by the shell theorem. So, the remaining mass is proportional to , and the gravitational force exerted on it is proportional to , so to , so is linear in .
These results were important to Newton's analysis of planetary motion; they are not immediately obvious, but they can be proven with calculus. (Alternatively, Gauss's law for gravity offers a much simpler way to prove the same results.)
In addition to gravity, the shell theorem can also be used to describe the electric field generated by a static spherically symmetric charge density, or similarly for any other phenomenon that follows an inverse square law. The derivations below focus on gravity, but the results can easily be generalized to the electrostatic force. Moreover, the results can be generalized to the case of general ellipsoidal bodies.
Outside a shell
A solid, spherically symmetric body can be modelled as an infinite number of concentric, infinitesimally thin spherical shells. If one of these shells can be treated as a point mass, then a system of shells (i.e. the sphere) can also be treated as a point mass. Consider one such shell:
- Note: dθ appearing in the diagram refers to the small angle, not the arclength. The arclength is R dθ.
Applying Newton's Universal Law of Gravitation, the sum of the forces due to mass elements in the shaded band is
The total force on m, then, is simply the sum of the force exerted by all the bands. By shrinking the width of each band, and increasing the number of bands, the sum becomes an integral expression:
Since G and m are constants, they may be taken out of the integral:
To evaluate this integral, one must first express dM as a function of dθ
The total surface of a spherical shell is
while the surface of the thin slice between θ and θ + dθ is
If the mass of the shell is M, one therefore has that
By the law of cosines,
These two relations link the three parameters θ, s and φ that appear in the integral together. When θ increases from 0 to π radians, φ varies from the initial value 0 to a maximal value to finally return to zero for θ = π. s on the other hand increases from the initial value r − R to the final value r + R when θ increases from 0 to π radians. This is illustrated in the following animation:
- Note: As viewed from m, the shaded blue band appears as a thin annulus whose inner and outer diameters converge to R sin θ as dθ vanishes.
To find a primitive function to the integrand, one has to make s the independent integration variable instead of θ
Performing an implicit differentiation of the second of the "cosine law" expressions above yields
and one gets that
where the new integration variable s increases from r − R to r + R.
Inserting the expression for cos(φ) using the first of the "cosine law" expressions above, one finally gets that
A primitive function to the integrand is
and inserting the bounds r − R, r + R for the integration variable s in this primitive function, one gets that
saying that the gravitational force is the same as that of a point mass in the centre of the shell with the same mass.
Finally, integrate all infinitesimally thin spherical shell with mass of dM, and we can obtain the total gravity contribution of a solid ball to the object outside the ball
Between the radius of x to x + dx, dM can be expressed as a function of x, i.e.,
Therefore, the total gravity is
which suggests that the gravity of a solid spherical ball to an exterior object can be simplified as that of a point mass in the centre of the ball with the same mass.
Inside a shell
For a point inside the shell, the difference is that when θ is equal to zero, φ takes the value π radians and s the value R - r. When θ increases from 0 to π radians, φ decreases from the initial value π radians to zero and s increases from the initial value R - r to the value R + r.
This can all be seen in the following figure
Inserting these bounds into the primitive function
one gets that, in this case
saying that the net gravitational forces acting on the point mass from the mass elements of the shell, outside the measurement point, cancel out.
Generalization: If , the resultant force inside the shell is:
The above results into being identically zero if and only if
Outside the shell (i.e. r>R or r<-R):
Derivation using Gauss's law
The shell theorem is an immediate consequence of Gauss's law for gravity saying that
where M is the mass of the part of the spherically symmetric mass distribution that is inside the sphere with radius r and
The gravitational field of a spherically symmetric mass distribution like a mass point, a spherical shell or a homogenous sphere must also be spherically symmetric. If is a unit vector in the direction from the point of symmetry to another point the gravitational field at this other point must therefore be
where g(r) only depends on the distance r to the point of symmetry
Selecting the closed surface as a sphere with radius r with center at the point of symmetry the outward normal to a point on the surface, , is precisely the direction pointing away from the point of symmetry of the mass distribution.
One therefore has that
as the area of the sphere is 4πr2.
From Gauss's law it then follows that
Converses and generalizations
It is natural to ask whether the converse of the shell theorem is true, namely whether the result of the theorem implies the law of universal gravitation, or if there is some more general force law for which the theorem holds. More specifically, one may ask the question:
- Suppose there is a force between masses M and m, separated by a distance r of the form such that any spherically symmetric body affects external bodies as if its mass were concentrated at its centre. Then what form can the function take?
where G and can be constants taking any value. The first term is the familiar law of universal gravitation; the second is an additional force, analogous to the cosmological constant term in general relativity.
If we further constrain the force by requiring that the second part of the theorem also holds, namely that there is no force inside a hollow ball, we exclude the possibility of the additional term, and the inverse square law is indeed the unique force law satisfying the theorem.
On the other hand, if we relax the conditions, and require only that the field everywhere outside a spherically symmetric body is the same as the field from some point mass at the centre (of any mass), we allow a new class of solutions given by the Yukawa potential, of which the inverse square law is a special case.
Another generalization can be made for a disc by observing that
Doing all the intermediate calculations we get:
Note that in this example is expressed in .
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- Newton, Isaac (1687). Philosophiae Naturalis Principia Mathematica. London. pp. Theorem XXXI.
- Di Fratta, G. (2015). "The Newtonian Potential and the Demagnetizing Factors of the General Ellipsoid". arXiv: .
- Gurzadyan, Vahe (1985). "The cosmological constant in McCrea-Milne cosmological scheme". The Observatory. 105: 42–43. http://adsabs.harvard.edu/full/1985Obs...105...42G
- Arens, Richard (January 1, 1990). "Newton's observations about the field of a uniform thin spherical shell". Note di Matematica. X (Suppl. n. 1): 39–45.