Sherman Township, Antelope County, Nebraska

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Sherman Township
Township
Location in Antelope County
Location in Antelope County
Coordinates: 42°23′27″N 098°14′27″W / 42.39083°N 98.24083°W / 42.39083; -98.24083Coordinates: 42°23′27″N 098°14′27″W / 42.39083°N 98.24083°W / 42.39083; -98.24083
Country United States
State Nebraska
County Antelope
Area
 • Total 35.81 sq mi (92.75 km2)
 • Land 35.77 sq mi (92.65 km2)
 • Water 0.04 sq mi (0.10 km2)  0.11%
Elevation 1,755 ft (535 m)
Population (2010)
 • Total 103
 • Density 3/sq mi (1.1/km2)
GNIS feature ID 0838246

Sherman Township is one of twenty-four townships in Antelope County, Nebraska, United States. The population was 103 at the 2010 census.[1]

See also[edit]

References[edit]

  1. ^ "Geographic Identifiers: 2010 Demographic Profile Data (G001): Sherman township, Antelope County, Nebraska". U.S. Census Bureau, American Factfinder. Retrieved June 27, 2013. 

External links[edit]