Silkworth, Pennsylvania

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Silkworth, Pennsylvania
Census-designated place
Silkworth, Pennsylvania is located in Pennsylvania
Silkworth, Pennsylvania
Silkworth, Pennsylvania
Location within the state of Pennsylvania
Coordinates: 41°16′20″N 76°5′10″W / 41.27222°N 76.08611°W / 41.27222; -76.08611Coordinates: 41°16′20″N 76°5′10″W / 41.27222°N 76.08611°W / 41.27222; -76.08611
Country United States
State Pennsylvania
County Luzerne
Township Lehman Township
Area
 • Total 3.8 sq mi (9.9 km2)
 • Land 3.4 sq mi (8.8 km2)
 • Water 0.4 sq mi (1.1 km2)
Population (2010)
 • Total 820
 • Density 210/sq mi (83/km2)
Time zone Eastern (EST) (UTC-5)
 • Summer (DST) EDT (UTC-4)
Area code(s) 570

Silkworth is a census-designated place (CDP) in Lehman Township, Luzerne County, Pennsylvania, United States. The population was 820 at the 2010 census.[1]

Geography[edit]

Silkworth is located at 41°16′20″N 76°5′10″W / 41.27222°N 76.08611°W / 41.27222; -76.08611,[2] along Pennsylvania Route 29 on the west shore of Lake Silkworth, about 10 miles (16 km) northwest of the city of Nanticoke.

According to the United States Census Bureau, the CDP has a total area of 3.8 square miles (9.9 km2), of which 3.4 square miles (8.8 km2) is land and 0.42 square miles (1.1 km2), or 11.0%, is water.[3]

References[edit]