Sowmeeh-ye Haq

From Wikipedia, the free encyclopedia
  (Redirected from Sowma'eh-ye Malekshah)
Jump to: navigation, search
Sowmeeh-ye Haq
صومعه حق
Sowmeeh-ye Haq is located in Iran
Sowmeeh-ye Haq
Sowmeeh-ye Haq
Coordinates: 37°47′05″N 47°31′32″E / 37.78472°N 47.52556°E / 37.78472; 47.52556Coordinates: 37°47′05″N 47°31′32″E / 37.78472°N 47.52556°E / 37.78472; 47.52556
Country  Iran
Province East Azerbaijan
County Sarab
Bakhsh Central
Rural District Howmeh
Population (2006)
 • Total 110
Time zone IRST (UTC+3:30)
 • Summer (DST) IRDT (UTC+4:30)

Sowmeeh-ye Haq (Persian: صومعه حق‎‎, also Romanized as Şowme‘eh-ye Ḩaq; also known as Şowma‘eh-ye Malekshāh)[1] is a village in Howmeh Rural District, in the Central District of Sarab County, East Azerbaijan Province, Iran. At the 2006 census, its population was 110, in 27 families.[2]


  1. ^ Sowmeeh-ye Haq can be found at GEOnet Names Server, at this link, by opening the Advanced Search box, entering "-3804068" in the "Unique Feature Id" form, and clicking on "Search Database".
  2. ^ "Census of the Islamic Republic of Iran, 1385 (2006)". Islamic Republic of Iran. Archived from the original (Excel) on 2011-11-11.