|WikiProject Physics||(Rated C-class, Low-importance)|
Is the integration done properly? i dont think so, can someone double check this? Currently it states that the integration of dVb=Vbe(V-Vb) equals ln(1-y)=Vbe/V. I think it should equal ln(1-Y)=Vbe. —Preceding unsigned comment added by 184.108.40.206 (talk) 02:00, 11 February 2009 (UTC)
For better understanding it maybe would be nice to use $\log$ instead of $\ln$ an distinguish by this between the inversion of $\exp()$ and the logarithmic plotting.
The link to IUPAC Compendium of Chemical Terminolgy in the external links section is dead. Does anyone know where to redirect? — Preceding unsigned comment added by Physicsman19 (talk • contribs) 14:04, 28 July 2014 (UTC)