# Talk:Brayton cycle

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Should the information on this page be moved to Gas turbine?? Pud 8 June 04, 8:58 PST

## Barber?

"by Barber in 1791"

found it. I will include it. http://www.turbomachine.com/history/ —Preceding unsigned comment added by Ericg33 (talkcontribs) 21:49, 4 July 2008 (UTC)

Internal Fire By Lyle Cummins pages 52,53 and 54 — Preceding unsigned comment added by Imotorhead64 (talkcontribs) 10:39, 31 January 2013 (UTC)

## Efficiency

Some typical and maximum efficiency levels would be useful. Tobyw 12:12, 8 March 2006 (UTC)

In my opinion the formula of the efficiency of an ideal Brayton cycle should be changed from:

${\displaystyle \eta =1-{\frac {T_{1}}{T_{2}}}=1-\left({\frac {P_{1}}{P_{2}}}\right)^{(\gamma -1)/\gamma }}$

to:

${\displaystyle \eta =1-{\frac {Qin}{Qout}}=1-\left({\frac {P_{1}}{P_{2}}}\right)^{(\gamma -1)/\gamma }}$

in order to avoid confusion between the efficiency of Carnot's cycle (${\displaystyle \eta =1-{\frac {T_{1}}{T_{2}}}}$ ) and to eliminate any undesired reference to the points of the diagram, being that "T1" looks like the temperature of point 1 and so on. Am I wrong? Ciao --Simone Buralli (talk) 16:18, 9 February 2012 (UTC)

No, you're right. Go ahead and change it. I just read the page and I thought it was wrong and that T1 and T2 DID refer to the figures above them. —Preceding unsigned comment added by 155.207.26.69 (talk) 07:26, 10 May 2012‎

## Ideal Brayton Cycle

It's been a little while since my Heat Transfer and Thermal Fluid Systems classes, but I think that "compression ratio" is incorrect. "Pressure ratio," which is used in most of this article, is the correct term. Compression ratio is a ratio of volumes, while pressure ratio is a ratio of pressures. I don't have my books handy to confirm this, but hopefully someone will take a look at this and make the correction if necessary.

## The illustration

If I am not completely mistaken, the work output of the turbine is proportional to the area that is enclosed by the cycle diagrams. Consequently, the enclosed areas in both cycles diagrams should be of the same size. If this statement is correct, I think it will be nice to visualize this in the figure, e.g. by shading those areas and writing "W" or "Work out" into them.

Another issue: Does anyone know, whether the diagrams can also be used to derive a statement with respect to the efficiency of the turbine?Tomeasy (talk) 14:40, 6 December 2007 (UTC)

## Improve efficiency with an intercooler

I thought that with an intercooler the Brayton cycle has a worse thermal efficiency. Could this afirmation be checked? —Preceding unsigned comment added by 138.250.177.40 (talk) 17:30, 4 December 2010 (UTC)

## Jet engine?

The jet engine is an internal combustion engine? —Preceding unsigned comment added by 65.96.171.132 (talk) 04:37, 9 February 2011 (UTC)

do you have some reason you don't think the point between the compressor and expander is internal to the engine?—Preceding unsigned comment added by 110.175.57.184 (talk) 19:29, 23 March 2011

## Solar/Biodiesel?

What's this got to do with it? This should be removed from the article, it's simply just annoying and a waste of time for people looking for information about the cycle. If they want to know something about biodiesel or solar, they would look for it under other keywords. Looks like some commercial ad for www.solhyco.com. — Preceding unsigned comment added by 84.190.185.54 (talk) 14:12, 9 January 2012 (UTC)

I have extracted the information about the hybrid solar system from the heading "Model" and inserted it in a new sub-section: Brayton cycle#Solar Brayton cycle. Dolphin (t) 21:47, 9 January 2012 (UTC)

## Regenerator/Recuperator

A recuperator and a regenerator are essentially the same thing as far as this article is concerned (the only difference being in how they transfer heat from the exhaust to the compressed gas, which is not covered here). Considering that the recuperator section is pretty much just a repetition of the regenerator's section, I recommend it be either deleted or have both sections rewritten into a single, comprehensive section.

I agree, I was pretty confused what the difference were the way it is worded. — Preceding unsigned comment added by 128.200.204.101 (talk) 23:07, 29 October 2013 (UTC)

## Curious

The article has

In general, increasing the compression ratio is the most direct way to increase the overall power output of a Brayton system.[10]

Leaving aside the obvious point that the most direct way is to open the tap and burn more fuel, the sad fact is that figure 2 of the article shows that in some cases increasing the pressure ratio reduces the power output.

What does reference [10], Lichty, actually say, please?

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