|WikiProject Physics||(Rated C-class, High-importance)|
- 1 Untitled
- 2 copyedit to this difficult article, revert if I have screwed it up!
- 3 Why the "Delta potential barrier" section?
- 4 Redundancy concerning the Delta potential barrier
- 5 Error in Derivation Section
- 6 Error in "Double-well Dirac delta function model" Section
- 7 error in bound state section?
- 8 For article
- 9 Error in the Bound State Section
- 10 Duplicated text from different Wikipedia article
This article should be linked with the "Delta function potential" article.
- Not sure what you mean. If you mean "merge" with Delta function potential, please note that the potential well and potential barrier are physically quite different. Bamse 14:55, 6 December 2006 (UTC)
Can someone, not I, remove all the first person pronouns in this article? This is not a physics lecture in which we all have our notebooks and pens out. Please reduce the size of the centrefold in the middle of the article too. Rintrah 16:52, 10 December 2006 (UTC)
copyedit to this difficult article, revert if I have screwed it up!
I did a copyedit as the article sounds like a lecture rather than an article. i will post a request at wikiproject physics for someone to take a look at it. --killing sparrows (chirp!) 05:44, 24 April 2007 (UTC)
Why the "Delta potential barrier" section?
Redundancy concerning the Delta potential barrier
I recognize the difference between the potential wells and potential barriers; and I can understand why both should be there. However, the solution to the time-independent Schrodinger equation for a delta potential barrier is derived twice in this article. If someone could combine these two derivations, I would greatly appreciate it. 11, December 2008 —Preceding unsigned comment added by 126.96.36.199 (talk) 22:06, 11 December 2008 (UTC)
Error in Derivation Section
I think there's an error. If then the left-hand side after integration should be [ψ′R(0) − ψ′L(0)] + λψ(0). And the signs in the following coefficients are also wrong. Could someone please check this. Thanks 188.8.131.52 (talk) 15:26, 16 February 2009 (UTC)
- You are right. I checked it again on paper. It also agrees with what I wrote a long time ago when creating this article. It seems some editor messed up the signs. You may want to compare the rest of the article with the old version I linked to above. bamse (talk) 15:57, 16 February 2009 (UTC)
Error in "Double-well Dirac delta function model" Section
I don't understand the d- solution for the double delta function potential. I thought one property of the Lambert W function was W(a*exp(a)) = a. This would mean the d- solution was zero for equal charges, not just for q = 1 / 2*R. Dickvidal (talk) 18:13, 16 September 2010 (UTC)
- This is a different property of the Lambert W function - calculate W(a*exp(a)) for any value a > -1/e - you will see that it is true --> by definition y = W(x) <--> x = y*exp(y); let x = a*exp(a), then y=a... I think it means the d- solution was zero for equal charges (not just for q = 1 / 2*R) as long as -qR > -1/e. That is, I considered only real value of W(z)... —Preceding unsigned comment added by Dickvidal (talk • contribs) 15:41, 22 November 2010 (UTC)
- The d=0 solution is the trivial solution for the -ve case. But there are 2 other non-trivial solutions, one for the +ve case and one for the -ve case. You can check these out with a computer algebra system. Do you have access to Maple or Mathematica? BTW, You have to be careful with this. x = W(x*exp(x)) in a certain range but W(x*exp(-x)) does not simplify to "x". The -ve d solution is correct and applies to a regime where e.g. q=1 and R is large. TonyMath (talk) 19:43, 22 November 2010 (UTC)
- I think you might me missing on the fact that the Lambert W function is multivalued i.e. has a infinite number of solutions. The two solutions given are solutions in the real plane valid for large values of R (asymptotic regime) that are real. The +ve d solution is valid for 0<R<infinity. The solution for the -ve "d" is a bit peculiar that the energy does go to zero (ie. vacuum) at a particular value of R but you can recover the solution at a different branch. See Lambert W function for more details. TonyMath (talk) 19:52, 22 November 2010 (UTC)
- Ok, I think I understand - both q and R are positive, and given that the arguement of the Lambert W function is -qR*e**(-qR), relatively small, and negative, there are two real values of the Lambert W function...only one gives d- equal to zero... —Preceding unsigned comment added by Dickvidal (talk • contribs) 12:33, 23 November 2010 (UTC)
error in bound state section?
An important and interesting fact to add to the article would be that using the infinit square well with a finit wide of "a" we can find the energy and the wave function of the delta potential if we take the limiting case of the wide of the infinit potential to go to zero (a->0). If we do this we find that the infinit square well having countably many energy levels for a non zero width goes to only having only one possible bound state (only one energy level). Explaining the why is very insightful. —Preceding unsigned comment added by 184.108.40.206 (talk) 00:55, 25 November 2010 (UTC)
Error in the Bound State Section
- I think AL=BR=0 is wrong and should be AR=BL=0 because for E<0 k=iκ and AR*exp(ikx)=AR*exp(i*iκx)=AR*exp(-κx) which diverges for x<<0. While the term with AL does not diverge for x<<0. It's the same with BL and BR for x>>0. — Preceding unsigned comment added by 220.127.116.11 (talk) 22:37, 20 May 2012 (UTC)
Duplicated text from different Wikipedia article
The section "Remarks and Applications" is essentially copy and pasted from the article on Rectangular Potential Barrier.