Talk:Dimension (vector space)
|WikiProject Mathematics||(Rated C-class, Mid-importance)|
Why is the Hamil dimension well-defined? I would like to find a proof.
Have a tolerable existence. Eli <firstname.lastname@example.org>
- Have a look at the following web-page: http://www.uwm.edu/~adbell/Teaching/631/1999/631notes7L/node1.html . I haven't read it, but it seems to cover what you want. It first does the finite-dimensional case, and then explains how to modify the proof to deal with the infinite-dimensional case. --Zundark 09:47, 8 Oct 2003 (UTC)
I'm CERTAIN that the general case needs the axiom of choice. A Geek Tragedy 16:07, 1 July 2007 (UTC)
i am new to this. The first example is a three by three matrix, therefore, I cannot tell if the dimension dim = 3 is the number of rows or number of columns. — Preceding unsigned comment added by 184.108.40.206 (talk) 00:16, 17 May 2013 (UTC)