|WikiProject Mathematics||(Rated Start-class, Mid-priority)|
This explanation seems way to complicated. If someone understood this, they wouldn't need Wikipedia to explain it to them.
- To understand this you have to know that functions can behave analogously to vectors, and function spaces to vector spaces, and that a linear operator converts vectors to other vectors (or functions). If you multiply a vector by a scalar, you merely change a vector's magnitude, and not it's direction. So an eigenfunction is one whose direction is unchanged by the linear operator it is an eigenfunction of. ᛭ LokiClock (talk) 08:36, 13 July 2010 (UTC)
Slow down graphic
Please change the graphic example of the vibrating drum problem. It moves too fast and repeatedly and distracts the viewer from reading. I may even add that some pure soul with epilepsy will have a fit with it. —Preceding unsigned comment added by 22.214.171.124 (talk) 23:20, 19 August 2008 (UTC)
- Hit 'Esc' and it will stop. Oleg Alexandrov (talk) 02:57, 20 August 2008 (UTC)
- That's not a solution. Please change the graphic example of the vibrating drum problem.
Example in introduction
I understand why the example holds, but wouldn't f(x) = e^(kx) also be an eigenfunction of the simpler differential operation A = d/dx, with eigenvalue k? If so, why is the more complicated example offered? =/ — Preceding unsigned comment added by 126.96.36.199 (talk) 22:55, 21 January 2012 (UTC)