Talk:Hartogs' theorem

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Does the result imply that the function is actually analytic or just continuous? --ComplexZeta

Well, it implies continuity, and from there it is rather easy to get analyticity. Oleg Alexandrov (talk) 04:41, 21 June 2006 (UTC)

Incomplete definition of function[edit]

The function used as a counterexample is not defined at 0. I would fix it but I see the mistake actually comes from PlanetMath. -Set theorist (talk) 09:10, 25 November 2010 (UTC)

The proper function in this case is defined piecewise as f(x,y) = xy(x^2-y^2)/(x^2 + y^2) except at the origin, where f = 0. --Moly 21:24, 6 January 2011 (UTC) — Preceding unsigned comment added by Moly (talkcontribs)