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## uni

We are doing an piece at uni on address-binding (runtime, compile-time, load-time) is it just me or does wikipedia lack anything on this? Paige Master 20:26, 13 June 2006 (UTC)

There's a brief allusion to address binding in the register allocation article and the relocation (computer science). Is there anything more specific about address binding? --68.0.124.33 (talk) 02:50, 9 September 2008 (UTC)

One exbibyte is 260 bytes. How is 264 bytes 16 exbibytes? —Preceding unsigned comment added by Bookmunkie (talkcontribs) 00:31, 12 September 2007 (UTC)

264 = 24·260 = 16·260. -- BenRG 14:16, 12 September 2007 (UTC)

Isn't virtual address a synonym of linear address rather than logical address, as mentioned in the book Understanding The Linux Kernel written by Daniel & Macro and hereKefengx (talk) 14:16, 22 December 2008 (UTC)

I would say quite the opposite. Surely a linear address is a physical address?
But I could do with some help editing this.

SimonTrew (talk) 22:25, 24 February 2009 (UTC)

## Spelling Clarification

Why are we using gibi instead of giga and exibi instead of exa. —Preceding unsigned comment added by 67.110.32.253 (talk) 15:28, 31 August 2010 (UTC)

The infix "bi" is a way of describing the binary proximation, so as to avoid confusion concerning what sizes are actually the case. A kibibyte is therefore 1024 (2^10) bytes, rather than 1000 (10^3). Mebi- is 2^20, Gibi- is 2^30 and so on. The reason for this, of course, is that computers work in terms of bits and bytes - a binary numeral system rather than a decimal numeral system - and physical increments are manufactured in the same fashion. - 88.88.108.249 (talk) 09:56, 1 February 2011 (UTC)

## Dubious - virtual addresses translated by the processor

In the final section, 'Virtual memory versus physical memory', this statement is made: >When the program is actually executed, the virtual addresses are translated by the processor into real memory addresses. I'm not sure that's accurate. I take 'processor' here to mean 'CPU'. My understanding is that the Memory management unit, rather than the CPU, translates virtual addresses into physical addresses. The MMU does that using a Translation Lookaside Buffer. — Preceding unsigned comment added by PlaysWithLife (talkcontribs) 18:03, 29 August 2011 (UTC)

## 36-bit mainframe computers which used 18-bit word addressing

When I examined this example, at least three questions raised. First of all, "18-bit word addressing" is unclear itself, because could refer either to the address bus (addresses are 18-bit words) or to the addressable data unit (18-bit words are addressed). Could someone add a link to specs?

Second, the relationship of this example to bytes and byte addressing is not expressed.

Third, "36-bit word-addressable machine with an 18-bit data bus" reads as a deep nonsense and the subsequent calculation seems flawed. If addresses were 36-bit, then we have had gigabytes of address space, which is obviously not the case. But the text explicitly states that the data bus is 18-bit – what is 36-bit indeed? Second time this "36-bit" appears in elusive context. But if data bus is 18-bit and we have 218 addresses, multiplication gives us 576 KB – exactly the half of 1.125 MiB mentioned. May be data are nevertheless 36-bit? But is this case referring to "18-bit data bus" is paradoxical and worthless.

Incnis Mrsi (talk) 21:05, 12 January 2012 (UTC)

The address bus has 18 bits, and it addresses 36-bit words. I updated the article with calculations. Sorry for delayed response, I'm not closely monitoring this article, I just check in from time to time. This whole article remains original research. Sometime I may try to update with some citations if I can find them. Feel free to ask for further clarification if you still have questions. Thanks Wbm1058 (talk) 17:59, 20 January 2012 (UTC)
… a 36-bit word-addressable machine with an 18-bit data bus addresses only 218 (262,144) 36-bit locations …
What is the sense and purpose of "18-bit data bus" in this context if "locations" are 36-bit?! Incnis Mrsi (talk) 18:19, 20 January 2012 (UTC)
sorry, I should have proof-read it better. It should have said address bus. Wbm1058 (talk) 18:38, 20 January 2012 (UTC)
it appears that error was introduced with this edit Wbm1058 (talk) 18:47, 20 January 2012 (UTC)
Thank you. Happily these gaps are filled now. Incnis Mrsi (talk) 20:29, 20 January 2012 (UTC)

## "Each memory location in a stored-program computer holds a binary number of some sort."

Well, of some sort covers a lot of ground, but it is not an adequate description for decimal machines such as the IBM 650 where a memory location held 10 bi-quinary coded decimal digits. While individual digits might be "a binary number of some sort", the 10 digit memory location is base 10, not 2; a decimal number irrespective of how the digits were encoded.50.136.247.190 (talk) 02:30, 31 October 2013 (UTC)

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