# Talk:United Nations Security Council election, November 1946

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## I count two surplus votes in the source

The math is simple: 3 × 54 -51 -45 -43 -13 -4 -4×1 = 2. I guess they messed up a bit. --${\displaystyle \color {Blue}{\mathcal {M}}}$${\displaystyle \color {Blue}{\vec {(e\ ,}}}$${\displaystyle \color {Blue}t)}$ 20:22, 25 November 2013 (UTC)

The result is perfectly plausible without there being an error. It just means that two states voted for only two states, rather than three. If fifty-two states voted for three and two for two, you wind up with fifty-four ballot papers and 160 votes cast. Sir Sputnik (talk) 20:32, 25 November 2013 (UTC)