United States presidential election in Arkansas, 1992
|Elections in Arkansas|
The 1992 United States presidential election in Arkansas took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose six representatives, or electors to the Electoral College, who voted for President and Vice President.
Arkansas was won by the state's Governor Bill Clinton (D) with 53.21% of the popular vote over incumbent President George H.W. Bush (R-Texas) with 35.48%. Businessman Ross Perot (I-Texas) finished in third with 10.43% of the popular vote. Clinton ultimately won the national vote, defeating incumbent President Bush. Clinton was Governor of Arkansas at the time, and as he was popular within the state, he easily won by a margin of 17.73%, making it the first time that Arkansas had voted Democratic since 1976 when it voted for Jimmy Carter. Arkansas and Washington, D.C. were the only contests in which Clinton, or any candidate, received over 50% of the popular vote.
After the 1996 election, Arkansas would then return to being solidly Republican.
|United States presidential election in Arkansas, 1992|
|Republican||George H.W. Bush||337,324||35.48%||0|
|New Alliance Party||Lenora Fulani||1,022||0.11%||0|
|America First||James "Bo" Gritz||819||0.09%||0|
|Natural Law||Dr. John Hagelin||764||0.08%||0|
|Democrats for Economic Recovery||Lyndon LaRouche||762||0.08%||0|