United States presidential election in Illinois, 1848

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United States presidential election in Illinois, 1848

← 1844 November 7, 1848 1852 →

  LewisCass (cropped).png Zachary Taylor restored and cropped (cropped).png Martin Van Buren by Mathew Brady c1855-58 (cropped).jpg
Nominee Lewis Cass Zachary Taylor Martin Van Buren
Party Democratic Whig Free Soil
Home state Michigan Louisiana New York
Running mate William O. Butler Millard Fillmore Charles F. Adams
Electoral vote 9 0 0
Popular vote 55,952 52,853 15,702
Percentage 44.91% 42.42% 12.60%

President before election

James K. Polk
Democratic

Elected President

Zachary Taylor
Whig

The 1848 United States presidential election in Illinois took place on November 7, 1848, as part of the 1848 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for President and Vice President.

Illinois voted for the Democratic candidate, Lewis Cass, over Whig candidate Zachary Taylor and Free Soil candidate Martin Van Buren. Cass won Illinois by a margin of 2.49%.

Results[edit]

United States presidential election in Illinois, 1848[1][2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Lewis Cass of Michigan William O. Butler of Kentucky 55,952 44.91% 9 100.00%
Whig Zachary Taylor of Louisiana Millard Fillmore of New York 52,853 42.42% 0 0.00%
Free Soil Martin Van Buren of New York Charles F. Adams, Sr. of Massachusetts 15,702 12.60% 0 0.00%
Clay Whig Henry Clay of Kentucky 89 0.07% 0 0.00%
Total 124,596 100.00% 9 100.00%

References[edit]

  1. ^ "1848 Presidential General Election Results - Illinois". U.S. Election Atlas. Retrieved 27 December 2013. 
  2. ^ "1848 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved 27 December 2013.