United States presidential election in Kentucky, 1824

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United States presidential election in Kentucky, 1824
← 1820 October 26 – December 2, 1824 1828 →
  Henry Clay.JPG Andrew Jackson.jpg
Nominee Henry Clay Andrew Jackson
Party Democratic-Republican Democratic-Republican
Home state Kentucky Tennessee
Running mate Nathan Sanford John C. Calhoun
Electoral vote 14 0
Popular vote 16,982 6,356
Percentage 72.77% 27.23%

The 1824 United States presidential election in Kentucky took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. Voters chose 14 representatives, or electors to the Electoral College, who voted for President and Vice President.

During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the Presidency. Kentucky voted for Henry Clay over Andrew Jackson, John Quincy Adams, and William H. Crawford. Clay won Kentucky, his home state, by a wide margin of 45.54%.


United States presidential election in Kentucky, 1824[1]
Party Candidate Votes Percentage Electoral votes
Democratic-Republican Henry Clay 16,982 72.77% 14
Democratic-Republican Andrew Jackson 6,356 27.23% 0
Totals 23,338 100.0% 14


  1. ^ "1824 Presidential General Election Results - Kentucky". U.S. Election Atlas. Retrieved 27 February 2013.