United States presidential election in Montana, 1912

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United States presidential election in Montana, 1912
← 1908 November 5, 1912 (1912-11-05) 1916 →
  Woodrow Wilson-H&E.jpg Theodore Roosevelt-Pach.jpg
Nominee Woodrow Wilson Theodore Roosevelt
Party Democratic Progressive
Home state New Jersey New York
Running mate Thomas R. Marshall Hiram Johnson
Electoral vote 4 0
Popular vote 27,941 22,456
Percentage 35.0% 28.1%

  William Howard Taft.jpg EugeneVictorDebs.png
Nominee William Howard Taft Eugene Victor Debs
Party Republican Socialist
Home state Ohio Indiana
Running mate Nicholas M. Butler

(replaced James S. Sherman)

Emil Seidel
Electoral vote 0 0
Popular vote 18,512 10,885
Percentage 23.2% 13.6%

County results

President before election

William Howard Taft

Elected President

Woodrow Wilson

The 1912 United States presidential election in Montana took place on November 5, 1912, throughout the continuous 48 states. This was the first time that Arizona and New Mexico took part in a presidential election having been admitted to the Union earlier in the year. Voters chose 4 representatives, or electors to the Electoral College, who voted for President and Vice President.

This election was a four-way contest. Montana voted for the Democratic nominee New Jersey Governor Woodrow Wilson over the Progressive nominee former President Theodore "Teddy" Roosevelt, Republican nominee President William Howard Taft, and Socialist Party of America nominee union leader Eugene V. Debs. Wilson won Montana by a margin of 6.87%.


United States presidential [1]
Party Candidate Votes Percentage Electoral votes
Democratic Woodrow Wilson 27,941 35.00% 4
Progressive Theodore Roosevelt 22,456 28.13% 0
Republican William Howard Taft 18,512 23.19% 0
Socialist Eugene V. Debs 10,885 13.64% 0
Prohibition Eugene Chafin 32 0.04% 0