United States presidential election in Montana, 1948

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United States presidential election in Montana, 1948
Montana
← 1944 November 2, 1948 1952 →
  Harry S. Truman.jpg ThomasDewey.png
Nominee Harry S. Truman Thomas E. Dewey
Party Democratic Republican
Home state Missouri New York
Running mate Alben W. Barkley Earl Warren
Electoral vote 4 0
Popular vote 119,071 96,770
Percentage 53.1% 43.2%

MT1948president.png
County results

President before election

Harry S. Truman
Democratic

Elected President

Harry S. Truman
Democratic

The 1948 United States presidential election in Montana took place on November 2, 1948, throughout the continuous 48 states. Voters chose 4 representatives, or electors to the Electoral College, who voted for President and Vice President.

Montana voted for the Democratic nominee, President Harry Truman, over the Republican nominee, New York Governor Thomas E. Dewey. Truman won Montana by a large margin of 9.94%.

Results[edit]

United States presidential [1]
Party Candidate Votes Percentage Electoral votes
Democratic Harry Truman (incumbent) 119,071 53.09% 4
Republican Thomas E. Dewey 96,770 43.15% 0
Progressive Henry Wallace 7,313 3.26% 0
Socialist Norman Thomas 695 0.31% 0
Prohibition Claude Watson 429 0.19% 0

References[edit]