United States presidential election in New Hampshire, 1824

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United States presidential election in New Hampshire, 1824
New Hampshire
1820 ←
October 26 – December 2, 1824 → 1828

  JohnQAdams.png WilliamHCrawford.png
Nominee John Quincy Adams William H. Crawford
Party Democratic-Republican Democratic-Republican
Home state Massachusetts Georgia
Running mate John C. Calhoun Nathaniel Macon
Electoral vote 8 0
Popular vote 9,389 643
Percentage 93.59% 6.41%

President before election

James Monroe

Elected President

John Quincy Adams

The 1824 United States presidential election in New Hampshire took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.

During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the Presidency. New Hampshire voted for John Quincy Adams over William H. Crawford, Andrew Jackson, and Henry Clay. Adams won New Hampshire by a margin of 87.18%.


United States presidential election in New Hampshire, 1824[1]
Party Candidate Votes Percentage Electoral votes
Democratic-Republican John Quincy Adams 9,389 93.59% 8
Democratic-Republican William H. Crawford 643 6.41% 0
Totals 10,032 100.0% 8


  1. ^ "1824 Presidential General Election Results - New Hampshire". U.S. Election Atlas. Retrieved 27 February 2013.