United States presidential election in New York, 1824

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United States presidential election in New York, 1824

← 1820 October 26 – December 2, 1824 1828 →
  JohnQAdams.png WilliamHCrawford.png
Nominee John Quincy Adams William H. Crawford
Party Democratic-Republican Democratic-Republican
Home state Massachusetts Georgia
Running mate John C. Calhoun Nathaniel Macon
Electoral vote 26 5

  Henry Clay.JPG Andrew Jackson.jpg
Nominee Henry Clay Andrew Jackson
Party Democratic-Republican Democratic-Republican
Home state Kentucky Tennessee
Running mate Nathan Sanford John C. Calhoun
Electoral vote 4 1

President before election

James Monroe
Democratic-Republican

Elected President

John Quincy Adams
Democratic-Republican

The 1824 United States presidential election in New York took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. The state legislature chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the Presidency. New York cast twenty-six electoral votes for John Quincy Adams, five for William H. Crawford, four for Henry Clay and one for Andrew Jackson.

Results[edit]

United States presidential election in New York, 1824[1]
Party Candidate Votes Percentage Electoral votes
Democratic-Republican John Quincy Adams 26
Democratic-Republican William H. Crawford 5
Democratic-Republican Henry Clay 4
Democratic-Republican Andrew Jackson 1
Totals 36

References[edit]

  1. ^ "Electoral Votes for President and Vice President 1821-1837". National Archives and Records Administration. Retrieved 28 February 2013.