United States presidential election in New York, 1868

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United States presidential election in New York, 1868

← 1864 November 3, 1868 1872 →

  Horatio Seymour - Brady-Handysmall.jpg Ulysses S Grant by Brady c1870-restored crop.jpg
Nominee Horatio Seymour Ulysses S. Grant
Party Democratic Republican
Home state New York Illinois
Running mate Francis Preston Blair, Jr. Schuyler Colfax
Electoral vote 33 0
Popular vote 429,883 419,888
Percentage 50.59% 49.41%

New york presidential results 1872235346354t.png

President before election

Andrew Johnson
Democratic

Elected President

Ulysses S. Grant
Republican

The 1868 United States presidential election in New York took place on November 3, 1868, as part of the 1868 United States presidential election. Voters chose 33 representatives, or electors to the Electoral College, who voted for president and vice president.

New York voted for the Democratic nominee, former Governor of New York Horatio Seymour, over the Republican nominee, General Ulysses S. Grant. Seymour won his home state by a very narrow margin of 1.18%, making him the first Democratic candidate since Franklin Pierce in 1852 to win the state. Although Grant won nationally, this election would also begin New York's role in US presidential elections as a heavily contested swing state, to which whoever candidate won New York would almost always win the presidential election.

Results[edit]

United States presidential election in New York, 1868[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Horatio Seymour of New York Francis Preston Blair, Jr. of Missouri 429,883 50.59% 33 100.00%
Republican Ulysses S. Grant of Illinois Schuyler Colfax of Indiana 419,888 49.41% 0 0.00%
Total 849,771 100.00% 33 100.00%


References[edit]