1948 United States presidential election in Pennsylvania

Main article: United States presidential election, 1948

United States presidential election in Pennsylvania, 1948

November 2, 1948

Nominee Thomas E. Dewey Harry S. Truman Party Republican Democratic Home state New York Missouri Running mate Earl Warren Alben W. Barkley Electoral vote 35 0 Popular vote 1,902,197 1,752,426 Percentage 50.93% 46.92%

County results

President before election Harry S. Truman Democratic Elected President Harry S. Truman Democratic

The 1948 United States presidential election in Pennsylvania took place on November 2, 1948 throughout the continuous 48 states. Voters chose 35 representatives, or electors to the Electoral College, who voted for President and Vice President.

Pennsylvania voted for the Republican nominee, New York Governor Thomas E. Dewey, over the Democratic nominee, President Harry Truman. Dewey won Pennsylvania by a margin of 4.01%. As of 2012, this is the last time that a Democrat won the national election without carrying Pennsylvania. It was also the last time until 1968 that a presidential candidate won the election without carrying the state.

Results

United States presidential
Party		Candidate	Votes	Percentage	Electoral votes
	Republican	Thomas E. Dewey	1,902,197	50.93%	35
	Democratic	Harry Truman	1,752,426	46.92%	0
	Progressive	Henry Wallace	55,161	1.48%	0
	Socialist	Norman Thomas	11,325	0.30%	0
	Prohibition	Claude Watson	10,338	0.28%	0
	Militant Workers	Farrell Dobbs	2,133	0.06%	0
	Industrial Government	Edward Teichert	1,461	0.04%	0
	Write-ins	Write-ins	107	0.00%	0