United States presidential election in Pennsylvania, 1992

From Wikipedia, the free encyclopedia
Jump to: navigation, search
United States presidential election in Pennsylvania, 1992
← 1988 November 3, 1992 1996 →
  44 Bill Clinton 3x4.jpg 43 George H.W. Bush 3x4.jpg Ross Perot.jpg
Nominee Bill Clinton George H.W. Bush Ross Perot
Party Democratic Republican Independent
Home state Arkansas Texas Texas
Running mate Al Gore Dan Quayle James Stockdale
Electoral vote 23 0 0
Popular vote 2,239,164 1,791,841 902,667
Percentage 45.2% 36.1% 18.2%

PA 1992 pres counties.png

President before election

George H. W. Bush

Elected President

Bill Clinton

Bush on campaign. Seen here speaking at the Norristown, Pennsylvania High School, September, 1992.

The 1992 United States presidential election in Pennsylvania took place on November 3, 1992 throughout all 50 states and D.C., which was part of the 1992 United States presidential election. Voters chose 23 representatives, or electors to the Electoral College, who voted for President and Vice President.

Pennsylvania was won by Governor Bill Clinton (D) by a margin of 9.02%.[1] Billionaire businessman Ross Perot (I-TX) finished in third with a significant 18.2% of the popular vote in Pennsylvania.[2]


United States presidential election in Pennsylvania, 1992[3]
Party Candidate Running mate Votes Percentage Electoral votes
Democratic Bill Clinton Al Gore 2,239,164 45.15% 23
Republican George H.W. Bush Dan Quayle 1,791,841 36.12% 0
Independent Ross Perot James Stockdale 902,667 18.20% 0
Libertarian Andre Marrou Nancy Lord 21,477 0.43% 0
New Alliance Party Lenora Fulani Maria Elizabeth Muñoz 4,661 0.09% 0
Totals 4,959,810 100.0% 23