1932 United States presidential election in Wisconsin

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1932 United States presidential election in Wisconsin

← 1928 November 8, 1932 1936 →

All 531 electoral votes of the Electoral College
266 electoral votes needed to win
  FDR in 1933.jpg President Hoover portrait.jpg
Nominee Franklin D. Roosevelt Herbert Hoover
Party Democratic Republican
Home state New York California
Running mate John Nance Garner Charles Curtis
Electoral vote 12 0
Popular vote 707,410 347,741
Percentage 63.46% 31.19%

President before election

Herbert Hoover
Republican

Elected President

Franklin D. Roosevelt
Democratic

The 1932 United States presidential election in Wisconsin was held on November 8, 1932 as part of the 1932 United States presidential election. State voters chose twelve electors to the Electoral College, who voted for president and vice president.

Democratic Party candidate Franklin D. Roosevelt won Wisconsin with 64% of the popular vote, winning the state's twelve electoral votes.[1]

With his win in Wisconsin, Roosevelt became the first Democratic presidential candidate since Woodrow Wilson in 1912 to carry the state and the first since Franklin Pierce in 1852 to win the state with a majority of the popular vote (Wilson's win in 1912 and Grover Cleveland's win in 1892 were only pluralities).

Results[edit]

1932 United States presidential election in Wisconsin
Party Candidate Votes Percentage Electoral votes
Democratic Franklin D. Roosevelt 707,410 63.46% 12
Republican Herbert Hoover 347,741 31.19% 0
Socialist Norman Thomas 53,379 4.79% 0
Communist William Z. Foster 3,112 0.28% 0
Totals 1,111,642 100.0% 12

References[edit]

  1. ^ "1932 Presidential General Election Results - Wisconsin". Retrieved August 19, 2016.