Uru Uru Lake

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Uru Uru Lake
Lago Uru Uru Bolivia Satellite map 67.09971W 18.png
Location Oruro Department
Coordinates 18°5′40″S 67°5′46″W / 18.09444°S 67.09611°W / -18.09444; -67.09611Coordinates: 18°5′40″S 67°5′46″W / 18.09444°S 67.09611°W / -18.09444; -67.09611
Primary inflows Río Desaguadero
Primary outflows Río Desaguadero, Laq'a Jawira
Basin countries Bolivia
Surface area 214 km2 (83 sq mi)
Max. depth 1.5 m (4 ft 11 in)
Surface elevation 3,686 m (12,093 ft)
Settlements Oruro, Machacamarca
Designated 11 July 2002

Uru Uru Lake is a lake in the Oruro Department in Bolivia. It is fed by the Desaguadero River. It is situated at an elevation of 3,686 m, its surface area is 214 km².

The lake is formed by the flow of the Desaguadero River at its mouth into Lake Poopó, over the extensive sedimentation known as "Santo Tomás" from the small hermitage found there that was completely inundated. The formation dates to 1962. The river connects Lake Titicaca and Lake Poopó.

The lake is a tourist attraction for boating and fishing, as it contains a large number of fish.

Oruro is located very near the shore, and is an industrial mining center.

See also[edit]