User talk:Jmmartingarcia

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Re: Rubik 4x4x4[edit]


I think 24!/2 is the right factor (after fixing the corner cubelets), if all the centre cubelets are distinguishable. The number of distinguishable permutations given is 24!/(4!6), assuming centre cubelets of the same colour are indistinguishable, and the odd/even factor of 2 should be included in that 4!6. Κσυπ Cyp   21:22, 2 August 2008 (UTC)