# User talk:Qniemiec

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## Imponderables (book series)

This is an automated message from 173.45.72.122. I have performed a search with the contents of Imponderables (book series), and it appears to be very similar to another Wikipedia page: Imponderables. It is possible that you have accidentally duplicated contents, or made an error while creating the page— you might want to look at the pages and see if that is the case. If you are intentionally trying to rename an article, please see Help:Moving a page for instructions on how to do this without copying and pasting. If you are trying to move or copy content from one article to a different one, please see Wikipedia:Copying within Wikipedia and be sure you have acknowledged the duplication of material in an edit summary to preserve attribution history.

It is possible that the bot is confused and found similarity where none actually exists. If that is the case, you can remove the tag from the article. 173.45.72.122 (talk) 12:46, 18 January 2011 (UTC)

## Imponderables

I just finished cleaning up your cut-and-paste move of Imponderables and Imponderables (book series). Next time, if you wish to move a page, please do so via the move function built into the site rather than cutting and pasting. This preserves the page history, which is required per Wikipedia's licensing terms. If you have any questions, let me know. Thanks! SchuminWeb (Talk) 20:09, 18 January 2011 (UTC)

## February 2011

Welcome to Wikipedia. We welcome and appreciate your contributions, including your edits to Square root, but we cannot accept original research. Original research also encompasses novel, unpublished syntheses of previously published material. Please be prepared to cite a reliable source for all of your information. Thank you. - DVdm (talk) 13:46, 15 February 2011 (UTC)

## culturesheet.org

Hi Qniemiec, I removed your links (one as a reference, one as an External Link) to culture sheet.org, because it is an open wiki and is not remotely reliable as a Wikipedia reference/source, or as an external link. See WP:ELNO and WP:RS for information on what meets the standards for sourcing and external links here. I know you can't be expected to know all the many policies and guidelines here. There are usually good reasons for them, though. I sometimes find it helpful to understand the reasons behind the guidelines, since the principles can often be applied in other areas. Thanks for helping out and editing here, First Light (talk) 17:33, 7 August 2011 (UTC)

## History of the Poles in the United States

Given your high fluency in Polish, I am reaching out to you in regards to the History of the Poles in the United States article. It has no Polish equivalent, and any time you can spend towards translating in any capacity would be much-appreciated. I would be more than happy to help any way that I can.

Thank you! Pola.mola (talk) 20:20, 19 February 2016 (UTC)

## ArbCom Elections 2016: Voting now open!

 Hello, Qniemiec. Voting in the 2016 Arbitration Committee elections is open from Monday, 00:00, 21 November through Sunday, 23:59, 4 December to all unblocked users who have registered an account before Wednesday, 00:00, 28 October 2016 and have made at least 150 mainspace edits before Sunday, 00:00, 1 November 2016. The Arbitration Committee is the panel of editors responsible for conducting the Wikipedia arbitration process. It has the authority to impose binding solutions to disputes between editors, primarily for serious conduct disputes the community has been unable to resolve. This includes the authority to impose site bans, topic bans, editing restrictions, and other measures needed to maintain our editing environment. The arbitration policy describes the Committee's roles and responsibilities in greater detail. If you wish to participate in the 2016 election, please review the candidates' statements and submit your choices on the voting page. MediaWiki message delivery (talk) 22:08, 21 November 2016 (UTC)

## ArbCom 2017 election voter message

 Hello, Qniemiec. Voting in the 2017 Arbitration Committee elections is now open until 23.59 on Sunday, 10 December. All users who registered an account before Saturday, 28 October 2017, made at least 150 mainspace edits before Wednesday, 1 November 2017 and are not currently blocked are eligible to vote. Users with alternate accounts may only vote once. The Arbitration Committee is the panel of editors responsible for conducting the Wikipedia arbitration process. It has the authority to impose binding solutions to disputes between editors, primarily for serious conduct disputes the community has been unable to resolve. This includes the authority to impose site bans, topic bans, editing restrictions, and other measures needed to maintain our editing environment. The arbitration policy describes the Committee's roles and responsibilities in greater detail. If you wish to participate in the 2017 election, please review the candidates and submit your choices on the voting page. MediaWiki message delivery (talk) 18:42, 3 December 2017 (UTC)

Back in December 2010, you uploaded , which appears on the page Pearson correlation coefficient. I believe that the lines are labeled wrong—the label “y=...” should be on the less steep line, and the label “x=...” should be on the steeper line. To see this, note that the slope of “y=...” is, by the standard formula, ${\displaystyle {\frac {\sigma _{xy}}{\sigma _{x}^{2}}}.}$ The coefficient of y in the regression of x on y is ${\displaystyle {\frac {\sigma _{xy}}{\sigma _{y}^{2}}}}$; but when you plot it in the graph with y on the vertical axis, the slope is the reciprocal of that, namely ${\displaystyle {\frac {\sigma _{y}^{2}}{\sigma _{xy}}}.}$ Comparing the slopes of the two lines by cross-multiplying and using ${\displaystyle \sigma _{xy}=\rho \cdot \sigma _{x}\sigma _{y}}$ and ${\displaystyle \rho ^{2}<1}$ shows that the slope of the “y=...” line is less than the slope of the “x=...” line with y plotted vertically.
Hi Loraof, are you sure? As you mentioned, the slope of the red line [ y=f(x) ] is ${\displaystyle {\frac {\sigma _{xy}}{\sigma _{x}^{2}}}.}$, as shown by the red slope triangle with Cov(x,y) as its vertical and Var(x) as its horizontal leg. And vice versa, the slope of the blue line [ x=f(y) ] would be ${\displaystyle {\frac {\sigma _{xy}}{\sigma _{y}^{2}}}}$, with Var(y) as the horizontal leg of the corresponding blue slope triangle, and Cov(x,y) as the vertical leg, if plotted against the y-axis. However, if put into a common diagram plotted against the x-axis (as shown above), positions of the blue line's parameters change, with Var(y) now becoming the vertical leg of the blue slope triangle, and Cov(x,y) the horizontal leg, i.e. this slope is ${\displaystyle {\frac {\sigma _{y}^{2}}{\sigma _{xy}}}.}$ then. So, up to this point we seem to agree, don't we? The rest is a question of how Cov(x,y) relates to Var(x) and/or Var(y): as long as the first keeps being greater than both Var(x) and Var(y), the figure will keep looking as drawn, while - if Cov(x,y) becomes less than Var(x) and/or Var(y) - the situation will change accordingly, i.e the way you proposes, with the slope of the “y=...” line being less than the slope of the “x=...” line then. So, does ${\displaystyle \sigma _{xy}=\rho \cdot \sigma _{x}\sigma _{y}}$ and ${\displaystyle \rho ^{2}<1}$ mean that this is always the case? Greetings --Qniemiec (talk) 14:13, 4 January 2018 (UTC)
It’s impossible for both Cov(x,y) > Var(x) and Cov(x,y) > Var(y). First, Cov(x,y) > Var(x) means ${\displaystyle \rho \sigma _{x}\sigma _{y}>\sigma _{x}^{2}}$ and thus ${\displaystyle \rho >{\frac {\sigma _{x}}{\sigma _{y}}},}$ which requires ${\displaystyle \sigma _{x}<\sigma _{y}}$ since ${\displaystyle \rho <1.}$ But by parallel reasoning, Cov(x,y) > Var(y) requires ${\displaystyle \rho >{\frac {\sigma _{y}}{\sigma _{x}}},}$ which requires ${\displaystyle \sigma _{y}<\sigma _{x}}$ since ${\displaystyle \rho <1.}$ Since these contradict each other, the case shown in the graph cannot occur. Loraof (talk) 18:25, 4 January 2018 (UTC)
Hi, and thanks for that fast answer. So, if I understand you correctly, this means that if Cov(x,y) is > Var(x), then on the other hand Var(y) must always be > Cov(x,y), and vice versa? Respectively ${\displaystyle {\frac {\sigma _{xy}}{\sigma _{y}^{2}}}\cdot {\frac {\sigma _{xy}}{\sigma _{x}^{2}}}<1}$? By consequence this would mean that either ${\displaystyle \sigma _{y}^{2}>\sigma _{xy}>\sigma _{x}^{2}}$ , or ${\displaystyle \sigma _{x}^{2}>\sigma _{xy}>\sigma _{y}^{2}}$ always applied? If that's the essence of what you've tried to explain to me, I will update the figure accordingly as soon as possible. Greetings --Qniemiec (talk) 20:18, 4 January 2018 (UTC)
That’s right, except that we could also have ${\displaystyle \sigma _{y}^{2}>\sigma _{x}^{2}>\sigma _{xy}}$ or ${\displaystyle \sigma _{x}^{2}>\sigma _{y}^{2}>\sigma _{xy}}$ – these occur if the correlation is very low. Thanks! Loraof (talk) 20:31, 4 January 2018 (UTC)