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Varzob is located in Tajikistan
Location in Tajikistan
Coordinates: 38°46′25″N 068°49′04″E / 38.77361°N 68.81778°E / 38.77361; 68.81778Coordinates: 38°46′25″N 068°49′04″E / 38.77361°N 68.81778°E / 38.77361; 68.81778
CountryFlag of Tajikistan.svg Tajikistan
RegionDistricts of Republican Subordination
DistrictVarzob District
1,108 m (3,635 ft)
Time zoneGMT/UTC + 05:00 hour

Varzob (Tajik: Варзоб) is a settlement in Varzob District, Districts of Republican Subordination, Tajikistan, in central Asia.[1] It is the administrative center for the Varzob District.[2]


Varzob is located on the left (east) bank of the river Varzob, about 25 km north of Dushanbe. The village of Begar[3] lies about 2.5 km north of Varzob on the right bank of the river, and the village of Varzobkala[4] lies just .75 km south of Varzob on the right bank of the river.

There are seven rivers in the area: the Varzob, the Simiganj, the Sioma, the Seer, the Vakhsh, the Amoo, and the Sorhob.

View from Bigar table. 4 km north from the Varzob centre. Elevation: 1530m. 38°47′58″N 68°50′19″E / 38.799316°N 68.838658°E / 38.799316; 68.838658