Zakiabad, Alborz

From Wikipedia, the free encyclopedia
Jump to: navigation, search
زكي اباد
Zakiabad is located in Iran
Coordinates: 35°50′08″N 50°40′38″E / 35.83556°N 50.67722°E / 35.83556; 50.67722Coordinates: 35°50′08″N 50°40′38″E / 35.83556°N 50.67722°E / 35.83556; 50.67722
Country  Iran
Province Alborz
County Savojbolagh
Bakhsh Chaharbagh
Rural District Ramjin
Population (2006)
 • Total 1,051
Time zone IRST (UTC+3:30)
 • Summer (DST) IRDT (UTC+4:30)

Zakiabad (Persian: زكي اباد‎‎, also Romanized as Zakīābād, Zakkiābād, and Zekīābād)[1] is a village in Ramjin Rural District, Chaharbagh District, Savojbolagh County, Alborz Province, Iran. At the 2006 census, its population was 1,051, in 286 families.[2]


  1. ^ Zakiabad can be found at GEOnet Names Server, at this link, by opening the Advanced Search box, entering "-3088841" in the "Unique Feature Id" form, and clicking on "Search Database".
  2. ^ "Census of the Islamic Republic of Iran, 1385 (2006)". Islamic Republic of Iran. Archived from the original (Excel) on 2011-11-11.