1990 Atlantic 10 Men's Basketball Tournament

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The 1990 Atlantic 10 Men's Basketball Tournament was played from March 3 to March 5, 1990 and March 8, 1990, at the Palestra in Philadelphia, Pennsylvania, except for the final that was played at McGonigle Hall in Philadelphia. The winner was named champion of the Atlantic 10 Conference and received an automatic bid to the 1990 NCAA Men's Division I Basketball Tournament. Temple University won the tournament. No other teams received bids to the NCAA Tournament. The top six teams in the conference received first-round byes.

Bracket[edit]

  First Round
March 3
Palestra, Philadelphia, PA
Quarterfinals
March 4
Palestra
Semifinals
March 5
Palestra
Final
March 8
McGonigle Hall, Philadelphia
                                     
        
  1  Temple 61  
    9  Duquesne 50  
8  Saint Joseph's 70
9  Duquesne 96  
  1  Temple 65  
  5  Rutgers 57  
        
        
  4  Rhode Island 79
    5  Rutgers 80  
      
        
  1  Temple 53
  6  Massachusetts 51
        
        
  2  Penn State 83
    7  George Washington 72  
7  George Washington 85
10  St. Bonaventure 77  
  2  Penn State 59
  6  Massachusetts 64  
        
        
  3  West Virginia 55
    6  Massachusetts 78