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Revision as of 01:58, 4 April 2022 by WwwTheW(talk | contribs)(inaccurracy (pun intended))
^If AC = a and BC = b. OC = AM of a and b, and radius r = QO = OG. Using Pythagoras' theorem, QC² = QO² + OC² ∴ QC = √QO² + OC² = QM. Using Pythagoras' theorem, OC² = OG² + GC² ∴ GC = √OC² − OG² = GM. Using similar triangles, HC/GC = GC/OC ∴ HC = GC²/OC = HM.
