1879 Rhode Island gubernatorial election
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The 1879 Rhode Island gubernatorial election was held on April 2, 1879. Incumbent Republican Charles C. Van Zandt defeated Democratic nominee Thomas W. Segar with 62.09% of the vote.
General election
Candidates
Major party candidates
- Charles C. Van Zandt, Republican
- Thomas W. Segar, Democratic
Other candidates
- Samuel Hill, Independent
Results
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Republican | Charles C. Van Zandt (incumbent) | 9,717 | 62.09% | ||
| Democratic | Thomas W. Segar | 5,506 | 35.18% | ||
| Greenback | Samuel Hill | 318 | 2.03% | ||
| Majority | 4,211 | ||||
| Turnout | |||||
| Republican hold | Swing | ||||
References
- ^ Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved November 1, 2020.