Equivalence of metrics

In the study of metric spaces in mathematics, there are various notions of two metrics on the same underlying space being "the same", or equivalent.

In the following, $X$ will denote a non-empty set and $d_{1}$ and $d_{2}$ will denote two metrics on $X$.

Topological equivalence

The two metrics $d_{1}$ and $d_{2}$ are said to be topologically equivalent if they generate the same topology on $X$. The adjective "topological" is often dropped. There are multiple ways of expressing this condition:

• a subset $A\subseteq X$ is $d_{1}$-open if and only if it is $d_{2}$-open;
• the open balls "nest": for any point $x\in X$ and any radius $r>0$, there exist radii $r',r''>0$ such that

$B_{r'}(x;d_{1})\subseteq B_{r}(x;d_{2})$ and $B_{r''}(x;d_{2})\subseteq B_{r}(x;d_{1}).$

• the identity function $I:X\to X$ is both $(d_{1},d_{2})$-continuous and $(d_{2},d_{1})$-continuous.

The following are sufficient but not necessary conditions for topological equivalence:

• there exists a strictly increasing, continuous, and subadditive $f:\mathbb {R} _{+}\to \mathbb {R}$ such that $d_{2}=f\circ d_{1}$.
• for each $x\in X$, there exist positive constants $\alpha$ and $\beta$ such that, for every point $y\in X$,

$\alpha d_{1}(x,y)\leq d_{2}(x,y)\leq \beta d_{1}(x,y).$

Strong equivalence

Two metrics $d_{1}$ and $d_{2}$ are strongly equivalent if and only if there exist positive constants $\alpha$ and $\beta$ such that, for every $x,y\in X$,

$\alpha d_{1}(x,y)\leq d_{2}(x,y)\leq \beta d_{1}(x,y).$

In contrast to the sufficient condition for topological equivalence listed above, strong equivalence requires that there is a single set of constants that holds for every pair of points in $X$, rather than potentially different constants associated with each point of $X$.

Strong equivalence of two metrics implies topological equivalence, but not vice versa. An intuitive reason why topological equivalence does not imply strong equivalence is that bounded sets under one metric are also bounded under a strongly equivalent metric, but not necessarily under a topologically equivalent metric.

In finite dimensional spaces, all metrics induced by the p-norm, including the euclidean metric, the taxicab metric, and the Chebyshev distance, are strongly equivalent.

Even if two metrics are strongly equivalent, not all properties of the respective metric spaces are preserved. For instance, a function from the space to itself might be a contraction mapping under one metric, but not necessarily under a strongly equivalent one.

Properties preserved by equivalence

• The continuity of a function is preserved if either the domain or range is remetrized by an equivalent metric, but uniform continuity is preserved only by strongly equivalent metrics.
• The differentiability of a function is preserved if either the domain or range is remetrized by a strongly equivalent metric.
• A metric that is strongly equivalent to a complete metric is also complete; the same is not true of equivalent metrics because homeomorphisms do not preserve completeness. For example, since $(0,1)$ and $\mathbb {R}$ are homeomorphic, the homeomorphism induces a metric on $(0,1)$ which is complete because $\mathbb {R}$ is, and generates the same topology as the usual one, yet $(0,1)$ with the usual metric is not complete, because the sequence $(2^{-n})_{n\in \mathbb {N} }$ is Cauchy but not convergent. (It is not Cauchy in the induced metric.)

References

• Tensor analysis on manifolds. Dover Publications. 1980. {{cite book}}: Cite uses deprecated parameter |authors= (help)
• Efe Ok (2007). Real analysis with economics applications. Princeton University Press. ISBN 0-691-11768-3.
• Henri Cartan (1971). Differential Calculus. Kershaw Publishing Company LTD. ISBN 0-395-12033-0.