List of area moments of inertia

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The following is list of area moments of inertia. The area moment of inertia or second moment of area has a unit of dimension length4, and should not be confused with the mass moment of inertia. If the piece is thin, however, the mass moment of inertia equals the areal density times the area moment of inertia. Each is with respect to a horizontal axis through the centroid of the given shape, unless otherwise specified.

Description Figure Area moment of inertia Comment Reference
a filled circular area of radius r Area moment of inertia of a circle.svg I_0 = \frac{\pi (2r)^4}{64} or I_0 = \frac{\pi (r)^4}{4} [1]
an annulus of inner radiusr1 and outer radiusr2 Area moment of inertia of a circular area.svg I_0 = \frac{\pi}{4} \left({r_2}^4-{r_1}^4\right) For thin tubes, this is approximately equal to: \pi \left(\frac{{r_2}+{r_1}}{2}\right)^3 \left({r_2}-{r_1}\right) or πr3t .
a filled circular sector of angle θ in radians and radius r with respect to an axis through the centroid of the sector and the centre of the circle Area moment of inertia of a circular sector.svg I_0 = \left(\theta -\sin\theta\right)\frac{r^4}{8}
a filled semicircle with radius r with respect to a horizontal line passing through the centroid of the area Area moment of inertia of a semicircle 2.svg I_0 = \left(\frac{\pi}{8} - \frac{8}{9\pi}\right)r^4 \approx 0.1098r^4 [2]
a filled semicircle as above but with respect to an axis collinear with the base Area moment of inertia of a semicircle.svg I = \frac{\pi r^4}{8} This is a consequence of the parallel axis theorem and the fact that the distance between these two axes is \frac{4r}{3\pi} [2]
a filled semicircle as above but with respect to a vertical axis through the centroid
Area moment of inertia of a semicircle 3.svg
I_0 = \frac{\pi r^4}{8} [2]
a filled quarter circle with radius r entirely in the 1st quadrant of the Cartesian coordinate system Area moment of inertia of a quartercircle.svg I = \frac{\pi r^4}{16} [3]
a filled quarter circle as above but with respect to a horizontal or vertical axis through the centroid Area moment of inertia of a quartercircle 2.svg I_0 = \left(\frac{\pi}{16}-\frac{4}{9\pi}\right)r^4 This is a consequence of the parallel axis theorem and the fact that the distance between these two axes is \frac{4r}{3\pi} [3]
a filled ellipse whose radius along the x-axis is a and whose radius along the y-axis is b Area moment of inertia of an ellipsis.svg I_0 = \frac{\pi}{4} ab^3
a filled rectangular area with a base width of b and height h Area moment of inertia of a rectangle.svg I_0 = \frac{bh^3}{12} [4]
a filled rectangular area as above but with respect to an axis collinear with the base Area moment of inertia of a rectangle 2.svg I = \frac{bh^3}{3} This is a result from the parallel axis theorem [4]
a filled rectangular area as above but with respect to an axis collinear, where r is the perpendicular distance from the centroid of the rectangle to the axis of interest I = \frac{bh^3}{12}+bhr^2 This is a result from the parallel axis theorem [4]
a filled triangular area with a base width of b and height h with respect to an axis through the centroid Area moment of inertia of a triangle.svg I_0 = \frac{bh^3}{36} [5]
a filled triangular area as above but with respect to an axis collinear with the base Area moment of inertia of a triangle 2.svg I = \frac{bh^3}{12} This is a consequence of the parallel axis theorem [5]
a filled regular hexagon with a side length of a Area moment of inertia of a regular hexagon.svg I_0 = \frac{5\sqrt{3}}{16}a^4 The result is valid for both a horizontal and a vertical axis through the centroid, and therefore is also valid for an axis with arbitrary direction that passes through the origin.

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