1992 United States presidential election in Maryland
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 County Results
Clinton—>70%
Clinton—60-70%
Clinton—50-60%
Clinton—40-50%
Bush—40-50%
Bush—50-60%
Bush—60-70%
Bush—>70%
Perot—40-50% | |||||||||||||||||||||||||||||||||
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| Elections in Maryland |
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 Government |
The 1992 United States presidential election in Maryland took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose ten representatives, or electors to the Electoral College, who voted for President and Vice President.
Maryland was won by Governor Bill Clinton (D-Arkansas) with 49.80% of the popular vote over incumbent President George H.W. Bush (R-Texas) with 35.62%. Businessman Ross Perot (I-Texas) finished in third with 14.18% of the popular vote.[1] Clinton ultimately won the national vote, defeating incumbent President Bush.[2]
Results
| United States presidential election in Maryland, 1992[1] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic | Bill Clinton | 988,571 | 49.80% | 10 | |
| Republican | George H.W. Bush | 707,094 | 35.62% | 0 | |
| Independent | Ross Perot | 281,414 | 14.18% | 0 | |
| Libertarian | Andre Marrou | 4,715 | 0.24% | 0 | |
| New Alliance | Lenora Fulani | 2,786 | 0.14% | 0 | |
| N/A | Write-ins | 466 | 0.02% | 0 | |
| Totals | 1,985,046 | 100.0% | 10 | ||
References
- ^ a b "1992 Presidential General Election Results - Maryland". U.S. Election Atlas. Retrieved 8 June 2012.
- ^ "1992 Presidential General Election Results". U.S. Election Atlas. Retrieved 8 June 2012.
