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or one unit can be computed by the formula: :<math>~ T = \frac{\, 1,200 \,}{W} ~</math> where: {{mvar|T}} is the unit time, or ''dit'' duration in milliseconds...

\equiv \left| \boldsymbol{p} \right| = \hbar k = \frac{\, h \nu \,}{c} = \frac{\, h \,}{\lambda} ~.</math> ===Polarization and spin angular momentum===...

{{mvar|b, c, d}} are nonzero, the division rule is :<math>\frac{\,\dfrac{a}{b}\,} {\dfrac{c}{d}} = \frac{ad}{bc}.</math> Thus, dividing {{tmath|\tfrac a b}}...

transform of the derivative is given by <math display="block">\widehat{f'\,}(\xi) = \mathcal{F}\left\{ \frac{d}{dx} f(x)\right\} = i 2\pi \xi\hat{f}(\xi)...

<math>\left\langle\phi^0\right\rangle = \tfrac{1}{\sqrt{2\,}} v</math>, where <math>v = \tfrac{1}{\sqrt{\lambda \,}} \left|\mu_\text{H}\right|</math>. The measured...

confidence interval#Wald interval}} : <math> \widehat{p\,} \pm z \sqrt{ \frac{ \widehat{p\,} ( 1 -\widehat{p\,} )}{ n } } .</math> A [[continuity correction]]...

2\pi r k\,}{n} \\ & {} - \frac{1}{2\pi}\sin\frac{2\pi k}{n}\cdot\!\int_0^\infty \!\!\frac{\,e^{-nx}\!\cdot\log x\,}{\,\cosh x -\cos( 2\pi k/n )\,}\,{\mathrm...

radius ({{mvar|r}}{{sub|p}}) is <math> \frac{\, r_\text{a} \,}{ r_\text{p} } = \frac{\, 1 + e \,}{ 1 - e } \text{ ≈ 1.03399 .}</math> ==Examples== [[File:Eccentricity...

\cfrac{2^2}{10 + \cfrac{2^2}{14 + \ddots\,}}}} = 7 + \cfrac{2}{5 + \cfrac{1}{7 + \cfrac{1}{9 + \cfrac{1}{11 + \ddots\,}}}}</math> This formula also converges...

subtracting it: : <math> \widehat{\theta\,}^*_\text{mle} = \widehat{\theta\,}_\text{mle} - \widehat{b\,} ~ . </math> This estimator is unbiased up...

\text{Frequency domain} & S & = & S_\text{RE} & + & \overbrace{\,i\ S_\text{IO}\,} & + & i S_\text{IE} & + & S_\text{RO} \end{array} </math> From this, various...

expansion]]: <math display="block"> \alpha = \frac{\,1\,}{V} \left( \frac{\partial V}{\,\partial T\,} \right)_\mathsf{p} ~.</math> With this expression...

P^2=\frac{3\pi}{G}\frac{V}{M}\approx 10.896 \, \mathrm{ h^2 {\cdot} g {\cdot} cm^{-3} \,}\frac{V}{M}.</math> This way of expressing {{math|''G''}} shows the relationship...

particularly useful at the surface on the body is: :<math>v_e = \sqrt{2gr\,}</math> where ''r'' is the [[distance]] between the center of the body and...

\left[\, \frac{ \partial^2 L }{\, \partial \theta_i \, \partial \theta_j \,} \,\right]_{i,j=1,1}^{n_\mathrm{i},n_\mathrm{j}} \;</math> is [[negative definite]]...

\ \mbox{mol}\,e^{-}}{1 \ \mbox{mol}\,H_2 O} \cdot \frac{96,000 \ \mbox{C}\,}{1 \ \mbox{mol}\,e^{-}} = 2.1 \times 10^{8} C \ \, \ </math></div> of total...

<math> \sqrt{2\,}\, ,</math> and correspondingly multiply the <math> X_0 </math> and <math> X_{N-1}</math> terms by <math> 1/\sqrt{2\,} \,,</math> which...

\omega\,C)\,}</math> and the characteristic impedance can be expressed as :<math>Z_0 = \sqrt{\frac{R + j\,\omega\,L}{G + j\,\omega\,C}\,} ~\,.</math>...

<math>\quad h(\varphi)\;=\;\frac{P'K'}{PK}\;=\;\frac{\delta y}{R\delta\varphi\,}. </math> Since the meridians are mapped to lines of constant ''x'', we must...

temperature as a function of altitude for a mixed atmosphere is: <math> \frac{\, dS\,}{dz} = 0 </math> where {{mvar|S}} is the entropy. The isentropic equation...