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follows: Given words { w j : j ∈ N + i } {\displaystyle \{w_{j}:j\in N+i\}} , it takes their vector sum v := ∑ j ∈ N + i v w j {\displaystyle v:=\sum...

n v j , n α j , n , 1 − 1 x 1 β j , n , 1 ⋮ q j , n , i d j , n v j , n α j , n , i − 1 x i β j , n , i ) ) {\displaystyle Y_{V}={\begin{pmatrix}{\begin{pmatrix}q_{1...

{\displaystyle N_{j}} , N i , j {\displaystyle N_{i,j}} , O j {\displaystyle O_{j}} . This distribution has expected value E i , j = O j N i , j N j {\displaystyle...

[ K i , P k ] = i η i k P 0   , [ K i , P 0 ] = − i P i   , [ J m , J n ] = i ϵ m n k J k   , [ J m , K n ] = i ϵ m n k K k   , [ K m , K n ] = − i...

X_{k_{1}},o_{j}\in X_{k_{2}},o_{i},o_{j}\in Y_{l}\}} for some 1 ≤ i , j ≤ n , i ≠ j , 1 ≤ k , k 1 , k 2 ≤ r , k 1 ≠ k 2 , 1 ≤ l , l 1 , l 2 ≤ s , l 1...

(int i = j; i < n; ++i) { arma::vec u((n*(n+1))/2, arma::fill::zeros); u(j*n+i-((j+1)*j)/2) = 1.0; arma::mat T(n,n, arma::fill::zeros); T(i,j) = 1.0; T(j...

e 2 ) n 2 + T ( e 3 ) n 3 = ∑ i = 1 3 T ( e i ) n i = ( σ i j e j ) n i = σ i j n i e j {\displaystyle {\begin{aligned}\mathbf {T} ^{(\mathbf {n} )}&=\mathbf...

S , μ j , { N i ≠ j } = − ( ∂ p ∂ μ j ) S , V { N i ≠ j } {\displaystyle \left({\frac {\partial N_{j}}{\partial V}}\right)_{S,\mu _{j},\{N_{i\neq j}\}}=-\left({\frac...

g j 1 i 1 g j 2 i 2 ⋯ g j n i n A i 1 i 2 ⋯ i n = A j 1 j 2 ⋯ j n {\displaystyle g^{j_{1}i_{1}}g^{j_{2}i_{2}}\cdots g^{j_{n}i_{n}}A_{i_{1}i_{2}\cdots...

j ) n i j N log ⁡ ( N ⋅ n i j a i b j ) × a i ! b j ! ( N − a i ) ! ( N − b j ) ! N ! n i j ! ( a i − n i j ) ! ( b j − n i j ) ! ( N − a i − b j + n...

indicial notation, N i = n i N = n i T j n j = n i n k τ j k n j . {\displaystyle N_{i}=n_{i}N=n_{i}T_{j}n_{j}=n_{i}n_{k}\tau _{jk}n_{j}.} The parallel shear...

_{i}+\lambda _{j}+n-i-j}{n-i-j}}} ( n  odd ) dim ⁡ U λ = ∏ 1 ≤ i < j ≤ n − 1 2 λ i − λ j − i + j − i + j ∏ 1 ≤ i ≤ j ≤ n − 1 2 λ i + λ j + n − i − j n − i − j {\displaystyle...

then: Z = n i × ( c i j × [ Z ] j ) = ( n i × c i j ) × [ Z ] j {\displaystyle Z=n_{i}\times (c_{ij}\times [Z]_{j})=(n_{i}\times c_{ij})\times [Z]_{j}}...

for which π ( i + m ( j − 1 ) ) = j + n ( i − 1 ) , i = 1 , … , m , j = 1 , … , n . {\displaystyle \pi (i+m(j-1))=j+n(i-1),\quad i=1,\dots ,m,\quad j=1...

the average distance between instances and their target neighbors ∑ i , j ∈ N i d ( x → i , x → j ) {\displaystyle \sum _{i,j\in N_{i}}d({\vec {x}}_{i}...

both factors. We hence can write ∀ i , j n i j = K {\displaystyle \forall i,j\;n_{ij}=K} , and ∀ i , j n i j = n i + ⋅ n + j n {\displaystyle \forall i...

∈ V α . ψ ( j N − i ( x ) ) ) {\displaystyle (\forall x\in V_{\alpha }.\psi (j^{N-i}(x)))} can be converted to the form ( ∀ x ∈ j N − i ( V α ) . ψ (...

area): j n , i = c i u i {\displaystyle \mathbf {j} _{{\rm {n}},\,i}=c_{i}\mathbf {u} _{i}} and the barycentric molar flux of component i is j n , i = c...

k = 1 − 2 C j k S j + S k = 1 − 2 ∑ i = 1 p m i n ( N i j , N i k ) ∑ i = 1 p ( N i j + N i k ) {\displaystyle BC_{jk}=1-{\frac {2C_{jk}}{S_{j}+S_{k}}}=1-{\frac...

Short: i as in French vite, Long: i as in English machine [i], [ç], [ʝ], [ɲ] i as in English machine, but short Κ κ kappa, κάππα [k] k as in English...