Jump to content

Talk:Stokes radius

Page contents not supported in other languages.
From Wikipedia, the free encyclopedia

This is an old revision of this page, as edited by Optics guy07 (talk | contribs) at 03:14, 5 October 2007. The present address (URL) is a permanent link to this revision, which may differ significantly from the current revision.

There is a sentence "since most molecules are not perfectly spherical, the Stokes radius ist smaller than the effective radius (or the rotational radius). " Does "ist" in the sentence mean is or isn't? Anyone has an idea?

Reply to previous comment

Does "ist" in the sentence mean is or isn't? Anyone has an idea?

It should be 'is' ('ist' is the German form of 'is').

There is also some inconsistency as to whether it's Stoke's or Stokes radius in this article.

HL

Suggestion

It would be helpful to know what the variables stand for.137.48.19.41 14:28, 20 October 2006 (UTC)[reply]

Correct form is Stokes' radius. So it is neither Stokes radius nor Stoke's radius.

Drag force calculations

At what velocity a particle of radius 10 micrometer will move in an airstream of flow 2.75 m/s? the motion of particle is in the same direction as that of airflow. —The preceding unsigned comment was added by 202.54.42.61 (talk) 13:23, 9 February 2007 (UTC).[reply]

What is D?

"...Stokes radius is proportional to frictional coefficient f and inverse proportional to viscosity η:..." but there is no D in the following equation