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1990 Big Sky Conference men's basketball tournament

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1990 Big Sky Conference men's basketball tournament
ClassificationDivision I
Season1989–90
Teams6
SiteBSU Pavilion
Boise, ID
ChampionsIdaho (4th title)
Winning coachKermit Davis (2nd title)
MVPRiley Smith (Idaho)
← 1989
1991 →

The 1990 Big Sky Conference Men's Basketball Tournament was held March 8–10 at the BSU Pavilion at Boise State University in Boise, Idaho.[1]

Defending champions Idaho defeated conference newcomers Eastern Washington in the championship game, 65–62, to take home their second consecutive, and fourth overall, Big Sky men's basketball tournament.

The Vandals, in turn, received an automatic bid to the 1990 NCAA Tournament. No other Big Sky members were invited.

Format

No new teams were added to the Big Sky prior to the 1989–90 season, leaving total membership at nine.

No changes were made to the tournament format. With teams ranked based on regular season conference records, just the top six teams were invited to the tournament. The two top seeds were given byes into the semifinals while the third- through sixth-seeded teams were placed and paired into the preliminary quarterfinal round.

Bracket

Quarterfinals
Thursday, March 8
Semifinals
Friday, March 9
Championship
Saturday, March 10
         
1 Idaho 80
5 Montana State 71
5 Montana State 69
4 Montana 57
1 Idaho 65
2 Eastern Washington 62
3 Nevada 66
6 Weber State 75
6 Weber State 67
2 Eastern Washington 83

See also

References

  1. ^ "1989-90 Big Sky Conference Season Summary". sports-reference.com. Sports Reference LLC. 2016. Retrieved May 2, 2016.