Jump to content

Lazarev Bay

Coordinates: 69°20′S 72°0′W / 69.333°S 72.000°W / -69.333; -72.000
From Wikipedia, the free encyclopedia

This is the current revision of this page, as edited by BrownHairedGirl (talk | contribs) at 02:11, 29 April 2022 (add {{Use dmy dates}}). The present address (URL) is a permanent link to this version.

(diff) ← Previous revision | Latest revision (diff) | Newer revision → (diff)

Lazarev Bay is a rectangular bay, 15 nautical miles (28 km) long and 13 nautical miles (24 km) wide, which separates Alexander Island from Rothschild Island and is bounded on the south side by the Wilkins Ice Shelf, which joins the east portion of Rothschild Island and the west portion of Alexander Island (partially Cape Vostok, the Havre Mountains and the Lassus Mountains). Two minor islands, Dint Island and Umber Island, lie merged within the ice of the Wilkins Ice Shelf within Lazarev Bay.

The north coast of Alexander Island was first seen from a great distance by the Russian expedition of 1821 under Fabian Gottlieb von Bellingshausen. The bay was first mapped from air photos taken by the Ronne Antarctic Research Expedition, 1947–48, by D. Searle of the Falkland Islands Dependencies Survey in 1960, and it was named by the UK Antarctic Place-Names Committee for Lieutenant Mikhail Petrovich Lazarev, second-in-command of Bellingshausen's expedition and commander of the sloop Mirnyy.[1]

See also

[edit]

Further reading

[edit]
[edit]

References

[edit]
  1. ^ "Lazarev Bay". Geographic Names Information System. United States Geological Survey, United States Department of the Interior. Retrieved 6 June 2013.

69°20′S 72°0′W / 69.333°S 72.000°W / -69.333; -72.000 Public Domain This article incorporates public domain material from "Lazarev Bay". Geographic Names Information System. United States Geological Survey.