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Precedence graph

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This is an old revision of this page, as edited by Juliusdejeu (talk | contribs) at 14:11, 15 April 2019 (Made sure the first example has right capitalisation, the last W(B) was W(b) before). The present address (URL) is a permanent link to this revision, which may differ significantly from the current revision.

A precedence graph, also named conflict graph and serializability graph, is used in the context of concurrency control in databases.

The precedence graph for a schedule S contains:

  • A node for each committed transaction in S
  • An arc from Ti to Tj if an action of Ti precedes and conflicts with one of Tj's actions.

Precedence graph examples

Example 1

Example 2

Example 2

A precedence graph of the schedule D, with 3 transactions. As there is a cycle (of length 2; with two edges) through the committed transactions T1 and T2, this schedule (history) is not Conflict serializable. Notice, that the commit of Transaction 2 does not have any meaning regarding the creation of a precedence graph.

Testing Serializability with Precedence Graph

Testing Serializability Example

Algorithm to test Conflict Serializability of a Schedule S along with an example schedule.

or

  1. For each transaction Tx participating in schedule S, create a node labeled Ti in the precedence graph. Thus the precedence graph contains T1, T2, T3.
  2. For each case in S where Tj executes a read_item(X) after Ti executes a write_item(X), create an edge (Ti → Tj) in the precedence graph. This occurs nowhere in the above example, as there is no read after write.
  3. For each case in S where Tj executes a write_item(X) after Ti executes a read_item(X), create an edge (Ti → Tj) in the precedence graph. This results in a directed edge from T1 to T2 (as T1 has R(A) before T2 having W(A)).
  4. For each case in S where Tj executes a write_item(X) after Ti executes a write_item(X), create an edge (Ti → Tj) in the precedence graph. This results in directed edges from T2 to T1, T2 to T3 and T1 to T3.
  5. The schedule S is serializable if and only if the precedence graph has no cycles. As T1 and T2 constitute a cycle, the above example is not (conflict) serializable.