Sędzin
Appearance
Sędzin | |
---|---|
Village | |
Coordinates: 52°44′N 18°34′E / 52.733°N 18.567°E | |
Country | Poland |
Voivodeship | Kuyavian-Pomeranian |
County | Aleksandrów |
Gmina | Zakrzewo |
Population (approx.) | 600 |
Sędzin [ˈsɛnd͡ʑin] is a village in the administrative district of Gmina Zakrzewo, within Aleksandrów County, Kuyavian-Pomeranian Voivodeship, in north-central Poland.[1] It lies 18 kilometres (11 mi) south-west of Aleksandrów Kujawski and 34 km (21 mi) south of Toruń.
The village has an approximate population of 600.
References