# Fractional ideal

(Redirected from Divisorial ideal)

In mathematics, in particular commutative algebra, the concept of fractional ideal is introduced in the context of integral domains and is particularly fruitful in the study of Dedekind domains. In some sense, fractional ideals of an integral domain are like ideals where denominators are allowed. In contexts where fractional ideals and ordinary ring ideals are both under discussion, the latter are sometimes termed integral ideals for clarity.

## Definition and basic results

Let R be an integral domain, and let K be its field of fractions. A fractional ideal of R is an R-submodule I of K such that there exists a non-zero rR such that rIR. The element r can be thought of as clearing out the denominators in I. The principal fractional ideals are those R-submodules of K generated by a single nonzero element of K. A fractional ideal I is contained in R if, and only if, it is an ('integral') ideal of R.

A fractional ideal I is called invertible if there is another fractional ideal J such that IJ = R (where IJ = { a1b1 + a2b2 + ... + anbn : aiI, biJ, nZ>0 } is called the product of the two fractional ideals). In this case, the fractional ideal J is uniquely determined and equal to the generalized ideal quotient

${\displaystyle (R:I)=\{x\in K:xI\subseteq R\}.}$

The set of invertible fractional ideals form an abelian group with respect to the above product, where the identity is the unit ideal R itself. This group is called the group of fractional ideals of R. The principal fractional ideals form a subgroup. A (nonzero) fractional ideal is invertible if, and only if, it is projective as an R-module.

Every finitely generated R-submodule of K is a fractional ideal and if R is noetherian these are all the fractional ideals of R.

## Dedekind domains

In Dedekind domains, the situation is much simpler. In particular, every non-zero fractional ideal is invertible. In fact, this property characterizes Dedekind domains: an integral domain is a Dedekind domain if, and only if, every non-zero fractional ideal is invertible.

The set of fractional ideals over a Dedekind domain ${\displaystyle R}$ is denoted ${\displaystyle {\text{Div}}(R)}$. Its quotient group of fractional ideals by the subgroup of principal fractional ideals is an important invariant of a Dedekind domain called the ideal class group.

## Number Fields

Recall that the ring of integers ${\displaystyle {\mathcal {O}}_{K}}$ of a number field ${\displaystyle K}$ is a Dedekind domain. We call a fractional ideal which is a subset of ${\displaystyle {\mathcal {O}}_{K}}$ integral. One of the important structure theorems for fractional ideals of a number field states that every fractional ideal ${\displaystyle I}$ decomposes uniquely up to ordering as

${\displaystyle I=({\mathfrak {p}}_{1}\ldots {\mathfrak {p}}_{n})({\mathfrak {q}}_{1}\ldots {\mathfrak {q}}_{m})^{-1}}$

for prime ideals ${\displaystyle {\mathfrak {p}}_{i},{\mathfrak {q}}_{j}\in {\text{Spec}}({\mathcal {O}}_{K})}$. For example, ${\displaystyle {\frac {2}{5}}{\mathcal {O}}_{\mathbb {Q} (i)}}$ factors as

${\displaystyle (1+i)(1-i)((1+2i)(1-2i))^{-1}}$

Also, because fractional ideals over a number field are all finitely generated we can clear denominators my multiplying by some ${\displaystyle \alpha }$ to get an ideal ${\displaystyle J}$. Hence

${\displaystyle I={\frac {1}{\alpha }}J}$

Another useful structure theorem is that integral fractional ideals are generated by up to ${\displaystyle 2}$ elements.

There is an exact sequence

${\displaystyle 0\to {\mathcal {O}}_{K}^{*}\to K^{*}\to {\text{Div}}({\mathcal {O}}_{K})\to C_{K}\to 0}$

associated to every number field, where ${\displaystyle C_{K}}$ is the ideal class group of ${\displaystyle {\mathcal {O}}_{K}}$.

## Examples

• ${\displaystyle {\frac {5}{4}}\cdot \mathbb {Z} }$ is a fractional ideal over ${\displaystyle \mathbb {Z} }$
• In ${\displaystyle \mathbb {Q} _{\zeta _{3}}}$ we have the factorization ${\displaystyle (3)=(2\zeta _{3}+1)^{2}}$. This is because if we multiply it out, we get
{\displaystyle {\begin{aligned}(2\zeta _{3}+1)^{2}&=4\zeta _{3}^{2}+4\zeta _{3}+1\\&=4(\zeta _{3}^{2}+\zeta _{3})+1\end{aligned}}}

Since ${\displaystyle \zeta _{3}}$ satisfies ${\displaystyle \zeta _{3}^{2}+\zeta _{3}=-1}$, our factorization makes sense.

• In ${\displaystyle \mathbb {Q} ({\sqrt {-23}})}$ we can multiply the fractional ideals ${\displaystyle I=(2,(1/2){\sqrt {-23}}-(1/2))}$ and ${\displaystyle J=(4,(1/2){\sqrt {-23}}+(3/2))}$ to get the ideal ${\displaystyle IJ=(-(1/2){\sqrt {-23}}-(3/2))}$

## Sage Examples

We can factor prime number as a product of fractional ideals fairly easily in sage

sage: k.<z3> = CyclotomicField(3)
sage: k.factor(2)
Fractional ideal (2)
sage: k.factor (5)
(Fractional ideal (zeta5 - 1))^4
sage: l.<z> = NumberField(x^2 + 5)
sage: l.factor(2)
(Fractional ideal (2, z + 1))^2


Constructing fractional ideals is easy as well. For example,

sage: l.<z> = NumberField(x^2 + 5)
sage: I = l.fractional_ideal(1/z)
Fractional ideal (-1/5*z)
sage: J = l.fractional_ideal(1/2)
Fractional ideal (1/2)
sage: I*J
Fractional ideal (-1/10*z)


## Divisorial ideal

Let ${\displaystyle {\tilde {I}}}$ denote the intersection of all principal fractional ideals containing a nonzero fractional ideal I. Equivalently,

${\displaystyle {\tilde {I}}=(R:(R:I)),}$

where as above

${\displaystyle (R:I)=\{x\in K:xI\subseteq R\}.}$

If ${\displaystyle {\tilde {I}}=I}$ then I is called divisorial.[1] In other words, a divisorial ideal is a nonzero intersection of some nonempty set of fractional principal ideals. If I is divisorial and J is a nonzero fractional ideal, then (I : J) is divisorial.

Let R be a local Krull domain (e.g., a Noetherian integrally closed local domain). Then R is a discrete valuation ring if and only if the maximal ideal of R is divisorial.[2]

An integral domain that satisfies the ascending chain conditions on divisorial ideals is called a Mori domain.[3]